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Formula for distance? - Answers

d=(Iv)t+1/2(a)t2 or distance is equal to initial velocity times time plus one half the product of acceleration and time squared Added: At linear velocity: d=r.t r=rate t=time Free fall from rest, starting rate = 0 d=0.5g.t2 g=acceleration due to gravity (mean value on earth: 9.8 m/s2) t=time Combined: d= ro.t + 0.5g.t2



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Formula for distance? - Answers

https://math.answers.com/math-and-arithmetic/Formula_for_distance

d=(Iv)t+1/2(a)t2 or distance is equal to initial velocity times time plus one half the product of acceleration and time squared Added: At linear velocity: d=r.t r=rate t=time Free fall from rest, starting rate = 0 d=0.5g.t2 g=acceleration due to gravity (mean value on earth: 9.8 m/s2) t=time Combined: d= ro.t + 0.5g.t2



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https://math.answers.com/math-and-arithmetic/Formula_for_distance

Formula for distance? - Answers

d=(Iv)t+1/2(a)t2 or distance is equal to initial velocity times time plus one half the product of acceleration and time squared Added: At linear velocity: d=r.t r=rate t=time Free fall from rest, starting rate = 0 d=0.5g.t2 g=acceleration due to gravity (mean value on earth: 9.8 m/s2) t=time Combined: d= ro.t + 0.5g.t2

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      d=(Iv)t+1/2(a)t2 or distance is equal to initial velocity times time plus one half the product of acceleration and time squared Added: At linear velocity: d=r.t r=rate t=time Free fall from rest, starting rate = 0 d=0.5g.t2 g=acceleration due to gravity (mean value on earth: 9.8 m/s2) t=time Combined: d= ro.t + 0.5g.t2

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