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Formula to calculate normality? - Answers

The calculation for normality isn't too hard, but you have to have some info before you can find it. You need 1 the number of equivalents. # mol * (subscript on first element of first compound/ number of that element are in the balanced equation) = # equivalents I am probably confusing you on finding equivalents, but there is not much else I can do. sorry Using 0.2489 g. of H2C2O4*2H20 is .00197mol so... .00197 * (2/1) = 3.94*10^-3 equvialents 2 The volume in liters # mL/1000 = #L say 43 ml / 1000 +.043 L so normality would be (3.94*10^-3)/ .043 = 9.16*10^-2 as normality.



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Formula to calculate normality? - Answers

https://math.answers.com/math-and-arithmetic/Formula_to_calculate_normality

The calculation for normality isn't too hard, but you have to have some info before you can find it. You need 1 the number of equivalents. # mol * (subscript on first element of first compound/ number of that element are in the balanced equation) = # equivalents I am probably confusing you on finding equivalents, but there is not much else I can do. sorry Using 0.2489 g. of H2C2O4*2H20 is .00197mol so... .00197 * (2/1) = 3.94*10^-3 equvialents 2 The volume in liters # mL/1000 = #L say 43 ml / 1000 +.043 L so normality would be (3.94*10^-3)/ .043 = 9.16*10^-2 as normality.



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https://math.answers.com/math-and-arithmetic/Formula_to_calculate_normality

Formula to calculate normality? - Answers

The calculation for normality isn't too hard, but you have to have some info before you can find it. You need 1 the number of equivalents. # mol * (subscript on first element of first compound/ number of that element are in the balanced equation) = # equivalents I am probably confusing you on finding equivalents, but there is not much else I can do. sorry Using 0.2489 g. of H2C2O4*2H20 is .00197mol so... .00197 * (2/1) = 3.94*10^-3 equvialents 2 The volume in liters # mL/1000 = #L say 43 ml / 1000 +.043 L so normality would be (3.94*10^-3)/ .043 = 9.16*10^-2 as normality.

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      The calculation for normality isn't too hard, but you have to have some info before you can find it. You need 1 the number of equivalents. # mol * (subscript on first element of first compound/ number of that element are in the balanced equation) = # equivalents I am probably confusing you on finding equivalents, but there is not much else I can do. sorry Using 0.2489 g. of H2C2O4*2H20 is .00197mol so... .00197 * (2/1) = 3.94*10^-3 equvialents 2 The volume in liters # mL/1000 = #L say 43 ml / 1000 +.043 L so normality would be (3.94*10^-3)/ .043 = 9.16*10^-2 as normality.

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