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How Represent square root of 8.47 on real line? - Answers

To represent the square root of 8.47 on the real line, first, calculate its approximate value, which is about 2.91, since ( \sqrt{8.47} ) is between ( \sqrt{8} ) (approximately 2.83) and ( \sqrt{9} ) (3). On the real line, locate the point corresponding to 2.91, which is slightly less than 3 but more than 2.83. You can mark this point to indicate the position of ( \sqrt{8.47} ).



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How Represent square root of 8.47 on real line? - Answers

https://math.answers.com/math-and-arithmetic/How_Represent_square_root_of_8.47_on_real_line

To represent the square root of 8.47 on the real line, first, calculate its approximate value, which is about 2.91, since ( \sqrt{8.47} ) is between ( \sqrt{8} ) (approximately 2.83) and ( \sqrt{9} ) (3). On the real line, locate the point corresponding to 2.91, which is slightly less than 3 but more than 2.83. You can mark this point to indicate the position of ( \sqrt{8.47} ).



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https://math.answers.com/math-and-arithmetic/How_Represent_square_root_of_8.47_on_real_line

How Represent square root of 8.47 on real line? - Answers

To represent the square root of 8.47 on the real line, first, calculate its approximate value, which is about 2.91, since ( \sqrt{8.47} ) is between ( \sqrt{8} ) (approximately 2.83) and ( \sqrt{9} ) (3). On the real line, locate the point corresponding to 2.91, which is slightly less than 3 but more than 2.83. You can mark this point to indicate the position of ( \sqrt{8.47} ).

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      To represent the square root of 8.47 on the real line, first, calculate its approximate value, which is about 2.91, since ( \sqrt{8.47} ) is between ( \sqrt{8} ) (approximately 2.83) and ( \sqrt{9} ) (3). On the real line, locate the point corresponding to 2.91, which is slightly less than 3 but more than 2.83. You can mark this point to indicate the position of ( \sqrt{8.47} ).

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