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How big square fits inside 36 inch circle? - Answers

The largest square that can fit inside a 36-inch diameter circle has its corners touching the circle. The diagonal of the square equals the diameter of the circle, which is 36 inches. Using the relationship between the side length (s) of the square and its diagonal (d) (where (d = s\sqrt{2})), the side length of the square is (s = \frac{36}{\sqrt{2}} \approx 25.45) inches. Thus, the side of the largest square that fits inside the circle is about 25.45 inches.



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How big square fits inside 36 inch circle? - Answers

https://math.answers.com/math-and-arithmetic/How_big_square_fits_inside_36_inch_circle

The largest square that can fit inside a 36-inch diameter circle has its corners touching the circle. The diagonal of the square equals the diameter of the circle, which is 36 inches. Using the relationship between the side length (s) of the square and its diagonal (d) (where (d = s\sqrt{2})), the side length of the square is (s = \frac{36}{\sqrt{2}} \approx 25.45) inches. Thus, the side of the largest square that fits inside the circle is about 25.45 inches.



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https://math.answers.com/math-and-arithmetic/How_big_square_fits_inside_36_inch_circle

How big square fits inside 36 inch circle? - Answers

The largest square that can fit inside a 36-inch diameter circle has its corners touching the circle. The diagonal of the square equals the diameter of the circle, which is 36 inches. Using the relationship between the side length (s) of the square and its diagonal (d) (where (d = s\sqrt{2})), the side length of the square is (s = \frac{36}{\sqrt{2}} \approx 25.45) inches. Thus, the side of the largest square that fits inside the circle is about 25.45 inches.

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      The largest square that can fit inside a 36-inch diameter circle has its corners touching the circle. The diagonal of the square equals the diameter of the circle, which is 36 inches. Using the relationship between the side length (s) of the square and its diagonal (d) (where (d = s\sqrt{2})), the side length of the square is (s = \frac{36}{\sqrt{2}} \approx 25.45) inches. Thus, the side of the largest square that fits inside the circle is about 25.45 inches.

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