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How can you compose functions and find inverse functions? - Answers
Compose functions: First you apply one function to the original input, then you apply a second function to the result.Inverse function: I'll give an example. Assume your function is f(x) = 3x + 1. You can write the function as:y = 3x + 1... and solve for "x". Finally, exchange "x" and "y". In this case, solving for "x", you get:y = 3x + 13x + 1 = y3x = y - 1x = (y - 1)/3If you exchange "x" and "y", you get:y = (x - 1)/3Or, using functional notation, and using the function name "g" for the inverse of "f":g(x) = (x-1)/3Obviously, actually solving for the "other variable" is not always easy, and sometimes you won't be able to write the inverse function in an explicit way.
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How can you compose functions and find inverse functions? - Answers
Compose functions: First you apply one function to the original input, then you apply a second function to the result.Inverse function: I'll give an example. Assume your function is f(x) = 3x + 1. You can write the function as:y = 3x + 1... and solve for "x". Finally, exchange "x" and "y". In this case, solving for "x", you get:y = 3x + 13x + 1 = y3x = y - 1x = (y - 1)/3If you exchange "x" and "y", you get:y = (x - 1)/3Or, using functional notation, and using the function name "g" for the inverse of "f":g(x) = (x-1)/3Obviously, actually solving for the "other variable" is not always easy, and sometimes you won't be able to write the inverse function in an explicit way.
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How can you compose functions and find inverse functions? - Answers
Compose functions: First you apply one function to the original input, then you apply a second function to the result.Inverse function: I'll give an example. Assume your function is f(x) = 3x + 1. You can write the function as:y = 3x + 1... and solve for "x". Finally, exchange "x" and "y". In this case, solving for "x", you get:y = 3x + 13x + 1 = y3x = y - 1x = (y - 1)/3If you exchange "x" and "y", you get:y = (x - 1)/3Or, using functional notation, and using the function name "g" for the inverse of "f":g(x) = (x-1)/3Obviously, actually solving for the "other variable" is not always easy, and sometimes you won't be able to write the inverse function in an explicit way.
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