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How can you do square root? - Answers

There is no simple way.There is one way which resembles long division but with a divisor which changes at each step and I regret that I cannot explain it here.Another method is based on iteration and using the Newton-Raphson method seems the simplest. The method is as follows:If you want to find the square root of a number n then define f(x) = x^2 – n.Then finding the square root of n is equivalent to solving f(x) = 0.Let f’(x) = 2x. This is the derivative of f(x) but you do not need to know that to use the N-R method.Start with x0 as the first guess.Then let xn+1 = xn - f(xn)/f’(xn) for n = 0, 1, 2, …Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer.It works even if your first guess is not so good:Suppose you want the square root of 7 and you start with x0 = 5 (a pretty poor choice since 52 is 25, which is nowhere near 7).Even so, x3 = 2.2362512515, which is less than 0.01% from the true value. Finally, remember that the negative value is also a square root.



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How can you do square root? - Answers

https://math.answers.com/math-and-arithmetic/How_can_you_do_square_root

There is no simple way.There is one way which resembles long division but with a divisor which changes at each step and I regret that I cannot explain it here.Another method is based on iteration and using the Newton-Raphson method seems the simplest. The method is as follows:If you want to find the square root of a number n then define f(x) = x^2 – n.Then finding the square root of n is equivalent to solving f(x) = 0.Let f’(x) = 2x. This is the derivative of f(x) but you do not need to know that to use the N-R method.Start with x0 as the first guess.Then let xn+1 = xn - f(xn)/f’(xn) for n = 0, 1, 2, …Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer.It works even if your first guess is not so good:Suppose you want the square root of 7 and you start with x0 = 5 (a pretty poor choice since 52 is 25, which is nowhere near 7).Even so, x3 = 2.2362512515, which is less than 0.01% from the true value. Finally, remember that the negative value is also a square root.



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https://math.answers.com/math-and-arithmetic/How_can_you_do_square_root

How can you do square root? - Answers

There is no simple way.There is one way which resembles long division but with a divisor which changes at each step and I regret that I cannot explain it here.Another method is based on iteration and using the Newton-Raphson method seems the simplest. The method is as follows:If you want to find the square root of a number n then define f(x) = x^2 – n.Then finding the square root of n is equivalent to solving f(x) = 0.Let f’(x) = 2x. This is the derivative of f(x) but you do not need to know that to use the N-R method.Start with x0 as the first guess.Then let xn+1 = xn - f(xn)/f’(xn) for n = 0, 1, 2, …Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer.It works even if your first guess is not so good:Suppose you want the square root of 7 and you start with x0 = 5 (a pretty poor choice since 52 is 25, which is nowhere near 7).Even so, x3 = 2.2362512515, which is less than 0.01% from the true value. Finally, remember that the negative value is also a square root.

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      There is no simple way.There is one way which resembles long division but with a divisor which changes at each step and I regret that I cannot explain it here.Another method is based on iteration and using the Newton-Raphson method seems the simplest. The method is as follows:If you want to find the square root of a number n then define f(x) = x^2 – n.Then finding the square root of n is equivalent to solving f(x) = 0.Let f’(x) = 2x. This is the derivative of f(x) but you do not need to know that to use the N-R method.Start with x0 as the first guess.Then let xn+1 = xn - f(xn)/f’(xn) for n = 0, 1, 2, …Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer.It works even if your first guess is not so good:Suppose you want the square root of 7 and you start with x0 = 5 (a pretty poor choice since 52 is 25, which is nowhere near 7).Even so, x3 = 2.2362512515, which is less than 0.01% from the true value. Finally, remember that the negative value is also a square root.
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