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How can you integrate a three variable functions? - Answers
Assuming you are integrating with respect to one of the three variables, you integrate normally. For example: ∫(x+y+z)dx = ∫ x dx + ∫ y dx + ∫ z dx (Integral of the sum is the sum of the integrals) = x^2/x + yx + zx + C Or a harder one: ∫ (sin^2(y)+sqrt(z))/x dx = (sin^2(y) + sqrt(z))*∫ 1/x dx (Factor out constants) = ln(x)*(sin^2(y) + sqrt(z)) tl;dr: just do it normally with normal integration rules
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How can you integrate a three variable functions? - Answers
Assuming you are integrating with respect to one of the three variables, you integrate normally. For example: ∫(x+y+z)dx = ∫ x dx + ∫ y dx + ∫ z dx (Integral of the sum is the sum of the integrals) = x^2/x + yx + zx + C Or a harder one: ∫ (sin^2(y)+sqrt(z))/x dx = (sin^2(y) + sqrt(z))*∫ 1/x dx (Factor out constants) = ln(x)*(sin^2(y) + sqrt(z)) tl;dr: just do it normally with normal integration rules
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How can you integrate a three variable functions? - Answers
Assuming you are integrating with respect to one of the three variables, you integrate normally. For example: ∫(x+y+z)dx = ∫ x dx + ∫ y dx + ∫ z dx (Integral of the sum is the sum of the integrals) = x^2/x + yx + zx + C Or a harder one: ∫ (sin^2(y)+sqrt(z))/x dx = (sin^2(y) + sqrt(z))*∫ 1/x dx (Factor out constants) = ln(x)*(sin^2(y) + sqrt(z)) tl;dr: just do it normally with normal integration rules
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