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How do find the interquartile range in your data? - Answers

Arrange the data in increasing order and count the number of data points = N. Find the integer K = N/2 or (N+1)/2. The Kth number in the ordered set is the median. Now consider only the numbers from the smallest to the median and find the median of this subset. This is the lower quartile = Q1. Then consider only the numbers from the original median to the largest. Find the median of this subset. It is the upper quartile = Q3. Then IQR = Q3 - Q1



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How do find the interquartile range in your data? - Answers

https://math.answers.com/math-and-arithmetic/How_do_find_the_interquartile_range_in_your_data

Arrange the data in increasing order and count the number of data points = N. Find the integer K = N/2 or (N+1)/2. The Kth number in the ordered set is the median. Now consider only the numbers from the smallest to the median and find the median of this subset. This is the lower quartile = Q1. Then consider only the numbers from the original median to the largest. Find the median of this subset. It is the upper quartile = Q3. Then IQR = Q3 - Q1



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https://math.answers.com/math-and-arithmetic/How_do_find_the_interquartile_range_in_your_data

How do find the interquartile range in your data? - Answers

Arrange the data in increasing order and count the number of data points = N. Find the integer K = N/2 or (N+1)/2. The Kth number in the ordered set is the median. Now consider only the numbers from the smallest to the median and find the median of this subset. This is the lower quartile = Q1. Then consider only the numbers from the original median to the largest. Find the median of this subset. It is the upper quartile = Q3. Then IQR = Q3 - Q1

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      Arrange the data in increasing order and count the number of data points = N. Find the integer K = N/2 or (N+1)/2. The Kth number in the ordered set is the median. Now consider only the numbers from the smallest to the median and find the median of this subset. This is the lower quartile = Q1. Then consider only the numbers from the original median to the largest. Find the median of this subset. It is the upper quartile = Q3. Then IQR = Q3 - Q1

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