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How do find the square root of 43? - Answers

If you have a non-scientific calculator you can use the Newton-Raphson method. Suppose you wish to find the square root of 7. Let f(x) = x2 - 43 so that f(x) = 0 when x is the square roo. That is, you want to find x such that f(x) = 0. Let f'(x) = 2x [f'(x) is the derivative of f(x) but you do not need to know that to use the N-R method.] Make a guess at the square root of 7, and call is x0. Then calculate xn+1 = xn - f(xn)/f'(xn) for n = 1, 2, 3, ... Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer. Even if your first guess is not so good: Suppose you start with x0 = 6 (a pretty poor choice since 62 is 36, which is not very near 43). Even so, x3 = 6.55744, which is less than 3 billionths of a percent from the true value. Finally, remember that the negative value is also a square root.



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How do find the square root of 43? - Answers

https://math.answers.com/math-and-arithmetic/How_do_find_the_square_root_of_43

If you have a non-scientific calculator you can use the Newton-Raphson method. Suppose you wish to find the square root of 7. Let f(x) = x2 - 43 so that f(x) = 0 when x is the square roo. That is, you want to find x such that f(x) = 0. Let f'(x) = 2x [f'(x) is the derivative of f(x) but you do not need to know that to use the N-R method.] Make a guess at the square root of 7, and call is x0. Then calculate xn+1 = xn - f(xn)/f'(xn) for n = 1, 2, 3, ... Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer. Even if your first guess is not so good: Suppose you start with x0 = 6 (a pretty poor choice since 62 is 36, which is not very near 43). Even so, x3 = 6.55744, which is less than 3 billionths of a percent from the true value. Finally, remember that the negative value is also a square root.



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https://math.answers.com/math-and-arithmetic/How_do_find_the_square_root_of_43

How do find the square root of 43? - Answers

If you have a non-scientific calculator you can use the Newton-Raphson method. Suppose you wish to find the square root of 7. Let f(x) = x2 - 43 so that f(x) = 0 when x is the square roo. That is, you want to find x such that f(x) = 0. Let f'(x) = 2x [f'(x) is the derivative of f(x) but you do not need to know that to use the N-R method.] Make a guess at the square root of 7, and call is x0. Then calculate xn+1 = xn - f(xn)/f'(xn) for n = 1, 2, 3, ... Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer. Even if your first guess is not so good: Suppose you start with x0 = 6 (a pretty poor choice since 62 is 36, which is not very near 43). Even so, x3 = 6.55744, which is less than 3 billionths of a percent from the true value. Finally, remember that the negative value is also a square root.

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      If you have a non-scientific calculator you can use the Newton-Raphson method. Suppose you wish to find the square root of 7. Let f(x) = x2 - 43 so that f(x) = 0 when x is the square roo. That is, you want to find x such that f(x) = 0. Let f'(x) = 2x [f'(x) is the derivative of f(x) but you do not need to know that to use the N-R method.] Make a guess at the square root of 7, and call is x0. Then calculate xn+1 = xn - f(xn)/f'(xn) for n = 1, 2, 3, ... Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer. Even if your first guess is not so good: Suppose you start with x0 = 6 (a pretty poor choice since 62 is 36, which is not very near 43). Even so, x3 = 6.55744, which is less than 3 billionths of a percent from the true value. Finally, remember that the negative value is also a square root.
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