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How do i completely facor 48x2-96? - Answers

To completely factor the expression (48x^2 - 96), first factor out the greatest common factor, which is 48: [ 48(x^2 - 2). ] Next, the expression (x^2 - 2) can be recognized as a difference of squares, which can be factored further as: [ 48(x - \sqrt{2})(x + \sqrt{2}). ] Thus, the completely factored form of the expression is (48(x - \sqrt{2})(x + \sqrt{2})).



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How do i completely facor 48x2-96? - Answers

https://math.answers.com/math-and-arithmetic/How_do_i_completely_facor_48x2-96

To completely factor the expression (48x^2 - 96), first factor out the greatest common factor, which is 48: [ 48(x^2 - 2). ] Next, the expression (x^2 - 2) can be recognized as a difference of squares, which can be factored further as: [ 48(x - \sqrt{2})(x + \sqrt{2}). ] Thus, the completely factored form of the expression is (48(x - \sqrt{2})(x + \sqrt{2})).



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https://math.answers.com/math-and-arithmetic/How_do_i_completely_facor_48x2-96

How do i completely facor 48x2-96? - Answers

To completely factor the expression (48x^2 - 96), first factor out the greatest common factor, which is 48: [ 48(x^2 - 2). ] Next, the expression (x^2 - 2) can be recognized as a difference of squares, which can be factored further as: [ 48(x - \sqrt{2})(x + \sqrt{2}). ] Thus, the completely factored form of the expression is (48(x - \sqrt{2})(x + \sqrt{2})).

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      To completely factor the expression (48x^2 - 96), first factor out the greatest common factor, which is 48: [ 48(x^2 - 2). ] Next, the expression (x^2 - 2) can be recognized as a difference of squares, which can be factored further as: [ 48(x - \sqrt{2})(x + \sqrt{2}). ] Thus, the completely factored form of the expression is (48(x - \sqrt{2})(x + \sqrt{2})).

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