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How do i solve this -3(4x 1) y2? - Answers

To solve the expression (-3(4x + 1)y^2), first, distribute (-3) to both terms inside the parentheses: (-3 \times 4x = -12x) and (-3 \times 1 = -3). This gives you (-12xy^2 - 3y^2). The expression cannot be simplified further without specific values for (x) and (y).



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How do i solve this -3(4x 1) y2? - Answers

https://math.answers.com/math-and-arithmetic/How_do_i_solve_this_-3(4x_1)_y2

To solve the expression (-3(4x + 1)y^2), first, distribute (-3) to both terms inside the parentheses: (-3 \times 4x = -12x) and (-3 \times 1 = -3). This gives you (-12xy^2 - 3y^2). The expression cannot be simplified further without specific values for (x) and (y).



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https://math.answers.com/math-and-arithmetic/How_do_i_solve_this_-3(4x_1)_y2

How do i solve this -3(4x 1) y2? - Answers

To solve the expression (-3(4x + 1)y^2), first, distribute (-3) to both terms inside the parentheses: (-3 \times 4x = -12x) and (-3 \times 1 = -3). This gives you (-12xy^2 - 3y^2). The expression cannot be simplified further without specific values for (x) and (y).

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      To solve the expression (-3(4x + 1)y^2), first, distribute (-3) to both terms inside the parentheses: (-3 \times 4x = -12x) and (-3 \times 1 = -3). This gives you (-12xy^2 - 3y^2). The expression cannot be simplified further without specific values for (x) and (y).

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