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How do we regroup 1578 - 6000 only regrouping once? - Answers

To regroup 1578 - 6000 by regrouping once, we can first think of 6000 as 6000 = 5000 + 1000. Then, we can subtract 5000 from 1578, which requires regrouping since 1578 is less than 5000. By borrowing 1 from the thousands place, we turn 1578 into 6578 (which is 1000 more), allowing us to calculate 6578 - 5000 = 1578. Finally, we subtract the remaining 1000 to get 1578 - 6000 = -4222.



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How do we regroup 1578 - 6000 only regrouping once? - Answers

https://math.answers.com/math-and-arithmetic/How_do_we_regroup_1578_-_6000_only_regrouping_once

To regroup 1578 - 6000 by regrouping once, we can first think of 6000 as 6000 = 5000 + 1000. Then, we can subtract 5000 from 1578, which requires regrouping since 1578 is less than 5000. By borrowing 1 from the thousands place, we turn 1578 into 6578 (which is 1000 more), allowing us to calculate 6578 - 5000 = 1578. Finally, we subtract the remaining 1000 to get 1578 - 6000 = -4222.



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https://math.answers.com/math-and-arithmetic/How_do_we_regroup_1578_-_6000_only_regrouping_once

How do we regroup 1578 - 6000 only regrouping once? - Answers

To regroup 1578 - 6000 by regrouping once, we can first think of 6000 as 6000 = 5000 + 1000. Then, we can subtract 5000 from 1578, which requires regrouping since 1578 is less than 5000. By borrowing 1 from the thousands place, we turn 1578 into 6578 (which is 1000 more), allowing us to calculate 6578 - 5000 = 1578. Finally, we subtract the remaining 1000 to get 1578 - 6000 = -4222.

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      To regroup 1578 - 6000 by regrouping once, we can first think of 6000 as 6000 = 5000 + 1000. Then, we can subtract 5000 from 1578, which requires regrouping since 1578 is less than 5000. By borrowing 1 from the thousands place, we turn 1578 into 6578 (which is 1000 more), allowing us to calculate 6578 - 5000 = 1578. Finally, we subtract the remaining 1000 to get 1578 - 6000 = -4222.

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