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https://math.answers.com/math-and-arithmetic/How_do_write_49_in_roman_numerals

How do write 49 in roman numerals? - Answers

ILThis is because I is 1 and L is 50. When a letter with a smaller value is placed just in front of a letter with a larger value, the small value must be subtracted from the larger value. So, 50-1 = 49.WrongCorect Answer is = XLIXand the reason is :-There can be only one subtracted numeral, so we can't write IIX for 8. Only I, X, and C can stand before a larger numeral to subtract from it, and they can't stand in front of numerals more than ten times their value; IX for 9 is fine, but we can't write IL for 49 or IM for 1,999 for that we have to write XLIX or MCMXCIX.



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How do write 49 in roman numerals? - Answers

https://math.answers.com/math-and-arithmetic/How_do_write_49_in_roman_numerals

ILThis is because I is 1 and L is 50. When a letter with a smaller value is placed just in front of a letter with a larger value, the small value must be subtracted from the larger value. So, 50-1 = 49.WrongCorect Answer is = XLIXand the reason is :-There can be only one subtracted numeral, so we can't write IIX for 8. Only I, X, and C can stand before a larger numeral to subtract from it, and they can't stand in front of numerals more than ten times their value; IX for 9 is fine, but we can't write IL for 49 or IM for 1,999 for that we have to write XLIX or MCMXCIX.



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https://math.answers.com/math-and-arithmetic/How_do_write_49_in_roman_numerals

How do write 49 in roman numerals? - Answers

ILThis is because I is 1 and L is 50. When a letter with a smaller value is placed just in front of a letter with a larger value, the small value must be subtracted from the larger value. So, 50-1 = 49.WrongCorect Answer is = XLIXand the reason is :-There can be only one subtracted numeral, so we can't write IIX for 8. Only I, X, and C can stand before a larger numeral to subtract from it, and they can't stand in front of numerals more than ten times their value; IX for 9 is fine, but we can't write IL for 49 or IM for 1,999 for that we have to write XLIX or MCMXCIX.

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      ILThis is because I is 1 and L is 50. When a letter with a smaller value is placed just in front of a letter with a larger value, the small value must be subtracted from the larger value. So, 50-1 = 49.WrongCorect Answer is = XLIXand the reason is :-There can be only one subtracted numeral, so we can't write IIX for 8. Only I, X, and C can stand before a larger numeral to subtract from it, and they can't stand in front of numerals more than ten times their value; IX for 9 is fine, but we can't write IL for 49 or IM for 1,999 for that we have to write XLIX or MCMXCIX.

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