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How do you Find the 18 term of the arithmetic sequence 3101724...? - Answers

To find the 18th term of the arithmetic sequence 3, 10, 17, 24..., first, identify the common difference. The difference between consecutive terms is 7 (10 - 3, 17 - 10, 24 - 17). The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 18th term: ( a_{18} = 3 + (18 - 1) \times 7 = 3 + 119 = 122 ).



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How do you Find the 18 term of the arithmetic sequence 3101724...? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_Find_the_18_term_of_the_arithmetic_sequence_3101724...

To find the 18th term of the arithmetic sequence 3, 10, 17, 24..., first, identify the common difference. The difference between consecutive terms is 7 (10 - 3, 17 - 10, 24 - 17). The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 18th term: ( a_{18} = 3 + (18 - 1) \times 7 = 3 + 119 = 122 ).



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https://math.answers.com/math-and-arithmetic/How_do_you_Find_the_18_term_of_the_arithmetic_sequence_3101724...

How do you Find the 18 term of the arithmetic sequence 3101724...? - Answers

To find the 18th term of the arithmetic sequence 3, 10, 17, 24..., first, identify the common difference. The difference between consecutive terms is 7 (10 - 3, 17 - 10, 24 - 17). The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 18th term: ( a_{18} = 3 + (18 - 1) \times 7 = 3 + 119 = 122 ).

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      To find the 18th term of the arithmetic sequence 3, 10, 17, 24..., first, identify the common difference. The difference between consecutive terms is 7 (10 - 3, 17 - 10, 24 - 17). The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 18th term: ( a_{18} = 3 + (18 - 1) \times 7 = 3 + 119 = 122 ).

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