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How do you calculate the interior angles of a polygon? - Answers

The formula for calculating the TOTAL of the interior angles of an n-sided polygon is: Angle Sum = 180 (n-2) degrees So for a regular polygon, each of the identical interior angles will be 180(n-2)/n e.g. triangle 180 (3-2) / 3 = 60 square 180 (4-2) / 4 = 90 pentagon 180 (5-2) / 5 = 108 heptagon 180 (7-2) / 7 = 128.57 (128 4/7)



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How do you calculate the interior angles of a polygon? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_calculate_the_interior_angles_of_a_polygon

The formula for calculating the TOTAL of the interior angles of an n-sided polygon is: Angle Sum = 180 (n-2) degrees So for a regular polygon, each of the identical interior angles will be 180(n-2)/n e.g. triangle 180 (3-2) / 3 = 60 square 180 (4-2) / 4 = 90 pentagon 180 (5-2) / 5 = 108 heptagon 180 (7-2) / 7 = 128.57 (128 4/7)



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https://math.answers.com/math-and-arithmetic/How_do_you_calculate_the_interior_angles_of_a_polygon

How do you calculate the interior angles of a polygon? - Answers

The formula for calculating the TOTAL of the interior angles of an n-sided polygon is: Angle Sum = 180 (n-2) degrees So for a regular polygon, each of the identical interior angles will be 180(n-2)/n e.g. triangle 180 (3-2) / 3 = 60 square 180 (4-2) / 4 = 90 pentagon 180 (5-2) / 5 = 108 heptagon 180 (7-2) / 7 = 128.57 (128 4/7)

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      The formula for calculating the TOTAL of the interior angles of an n-sided polygon is: Angle Sum = 180 (n-2) degrees So for a regular polygon, each of the identical interior angles will be 180(n-2)/n e.g. triangle 180 (3-2) / 3 = 60 square 180 (4-2) / 4 = 90 pentagon 180 (5-2) / 5 = 108 heptagon 180 (7-2) / 7 = 128.57 (128 4/7)

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