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How do you convert 121 base 4 to base 6? - Answers
1214 to base 6 = 41I. Convert 1214to base 10a. First we count each place digit in thenumber from right to left starting at 0.1 2 12 1 0 -----mb. Then since it is base 4, we multiply each digit by 3m, where m is thenumber we just counted for it.1 * 40 = 1 * 1 = 12 * 41= 2 * 4 = 81 * 42= 1 * 16 = 163. Add the products. 1 + 8 + 16 = 254. So 1214 = 2510II. Convert 25 to base 6a. 25 = 4 x 6 + 14 is 25÷ 66 is base 61 is the remainder (25÷6 = 4 remainder 1)b. take4 which is the quotient of25÷64 = 0 x 6 + 40 is 4÷ 66 is base 64 is the remainder (4÷6 = 0 remainder 4)III. From II a. & bTaking the remainders from bottom to top, we get 41.
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How do you convert 121 base 4 to base 6? - Answers
1214 to base 6 = 41I. Convert 1214to base 10a. First we count each place digit in thenumber from right to left starting at 0.1 2 12 1 0 -----mb. Then since it is base 4, we multiply each digit by 3m, where m is thenumber we just counted for it.1 * 40 = 1 * 1 = 12 * 41= 2 * 4 = 81 * 42= 1 * 16 = 163. Add the products. 1 + 8 + 16 = 254. So 1214 = 2510II. Convert 25 to base 6a. 25 = 4 x 6 + 14 is 25÷ 66 is base 61 is the remainder (25÷6 = 4 remainder 1)b. take4 which is the quotient of25÷64 = 0 x 6 + 40 is 4÷ 66 is base 64 is the remainder (4÷6 = 0 remainder 4)III. From II a. & bTaking the remainders from bottom to top, we get 41.
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How do you convert 121 base 4 to base 6? - Answers
1214 to base 6 = 41I. Convert 1214to base 10a. First we count each place digit in thenumber from right to left starting at 0.1 2 12 1 0 -----mb. Then since it is base 4, we multiply each digit by 3m, where m is thenumber we just counted for it.1 * 40 = 1 * 1 = 12 * 41= 2 * 4 = 81 * 42= 1 * 16 = 163. Add the products. 1 + 8 + 16 = 254. So 1214 = 2510II. Convert 25 to base 6a. 25 = 4 x 6 + 14 is 25÷ 66 is base 61 is the remainder (25÷6 = 4 remainder 1)b. take4 which is the quotient of25÷64 = 0 x 6 + 40 is 4÷ 66 is base 64 is the remainder (4÷6 = 0 remainder 4)III. From II a. & bTaking the remainders from bottom to top, we get 41.
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- og:description1214 to base 6 = 41I. Convert 1214to base 10a. First we count each place digit in thenumber from right to left starting at 0.1 2 12 1 0 -----mb. Then since it is base 4, we multiply each digit by 3m, where m is thenumber we just counted for it.1 * 40 = 1 * 1 = 12 * 41= 2 * 4 = 81 * 42= 1 * 16 = 163. Add the products. 1 + 8 + 16 = 254. So 1214 = 2510II. Convert 25 to base 6a. 25 = 4 x 6 + 14 is 25÷ 66 is base 61 is the remainder (25÷6 = 4 remainder 1)b. take4 which is the quotient of25÷64 = 0 x 6 + 40 is 4÷ 66 is base 64 is the remainder (4÷6 = 0 remainder 4)III. From II a. & bTaking the remainders from bottom to top, we get 41.
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