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How do you convert 131 5 to base 10? - Answers

To convert the number (131_5) from base 5 to base 10, you multiply each digit by (5) raised to the power of its position, starting from the right (position 0). So, (1 \times 5^2 + 3 \times 5^1 + 1 \times 5^0) equals (1 \times 25 + 3 \times 5 + 1 \times 1), which simplifies to (25 + 15 + 1 = 41). Therefore, (131_5) in base 10 is (41).



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How do you convert 131 5 to base 10? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_convert_131_5_to_base_10

To convert the number (131_5) from base 5 to base 10, you multiply each digit by (5) raised to the power of its position, starting from the right (position 0). So, (1 \times 5^2 + 3 \times 5^1 + 1 \times 5^0) equals (1 \times 25 + 3 \times 5 + 1 \times 1), which simplifies to (25 + 15 + 1 = 41). Therefore, (131_5) in base 10 is (41).



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https://math.answers.com/math-and-arithmetic/How_do_you_convert_131_5_to_base_10

How do you convert 131 5 to base 10? - Answers

To convert the number (131_5) from base 5 to base 10, you multiply each digit by (5) raised to the power of its position, starting from the right (position 0). So, (1 \times 5^2 + 3 \times 5^1 + 1 \times 5^0) equals (1 \times 25 + 3 \times 5 + 1 \times 1), which simplifies to (25 + 15 + 1 = 41). Therefore, (131_5) in base 10 is (41).

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      To convert the number (131_5) from base 5 to base 10, you multiply each digit by (5) raised to the power of its position, starting from the right (position 0). So, (1 \times 5^2 + 3 \times 5^1 + 1 \times 5^0) equals (1 \times 25 + 3 \times 5 + 1 \times 1), which simplifies to (25 + 15 + 1 = 41). Therefore, (131_5) in base 10 is (41).

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