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How do you convert SnCl22H2O to Sncl3? - Answers

To convert SnCl2·2H2O (tin(II) chloride dihydrate) to SnCl3 (tin(III) chloride), you first need to oxidize the tin from the +2 oxidation state to the +3 oxidation state. This can be achieved by reacting SnCl2 with an appropriate oxidizing agent, such as chlorine gas (Cl2) or hydrogen peroxide (H2O2). After the oxidation, the SnCl3 can be formed by ensuring the proper stoichiometry of chlorine to tin, while removing any water from the initial dihydrate form.



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How do you convert SnCl22H2O to Sncl3? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_convert_SnCl22H2O_to_Sncl3

To convert SnCl2·2H2O (tin(II) chloride dihydrate) to SnCl3 (tin(III) chloride), you first need to oxidize the tin from the +2 oxidation state to the +3 oxidation state. This can be achieved by reacting SnCl2 with an appropriate oxidizing agent, such as chlorine gas (Cl2) or hydrogen peroxide (H2O2). After the oxidation, the SnCl3 can be formed by ensuring the proper stoichiometry of chlorine to tin, while removing any water from the initial dihydrate form.



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https://math.answers.com/math-and-arithmetic/How_do_you_convert_SnCl22H2O_to_Sncl3

How do you convert SnCl22H2O to Sncl3? - Answers

To convert SnCl2·2H2O (tin(II) chloride dihydrate) to SnCl3 (tin(III) chloride), you first need to oxidize the tin from the +2 oxidation state to the +3 oxidation state. This can be achieved by reacting SnCl2 with an appropriate oxidizing agent, such as chlorine gas (Cl2) or hydrogen peroxide (H2O2). After the oxidation, the SnCl3 can be formed by ensuring the proper stoichiometry of chlorine to tin, while removing any water from the initial dihydrate form.

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      To convert SnCl2·2H2O (tin(II) chloride dihydrate) to SnCl3 (tin(III) chloride), you first need to oxidize the tin from the +2 oxidation state to the +3 oxidation state. This can be achieved by reacting SnCl2 with an appropriate oxidizing agent, such as chlorine gas (Cl2) or hydrogen peroxide (H2O2). After the oxidation, the SnCl3 can be formed by ensuring the proper stoichiometry of chlorine to tin, while removing any water from the initial dihydrate form.

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