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How do you determine a equation that is function? - Answers

If an equation is a function, then:The set of coordinates doesn't consists of the same first member. For instance, the set can't contain (1,2) and (1,1).There exists only a function within the specific interval. For instance, f(x) = x within -1 ≤ x ≤ 1 and x + 2 within 1 < x ≤ 3. If f(x) = x and x + 2 within -1 ≤ x ≤ 1, then this doesn't make an equation the function.



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How do you determine a equation that is function? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_determine_a_equation_that_is_function

If an equation is a function, then:The set of coordinates doesn't consists of the same first member. For instance, the set can't contain (1,2) and (1,1).There exists only a function within the specific interval. For instance, f(x) = x within -1 ≤ x ≤ 1 and x + 2 within 1 < x ≤ 3. If f(x) = x and x + 2 within -1 ≤ x ≤ 1, then this doesn't make an equation the function.



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https://math.answers.com/math-and-arithmetic/How_do_you_determine_a_equation_that_is_function

How do you determine a equation that is function? - Answers

If an equation is a function, then:The set of coordinates doesn't consists of the same first member. For instance, the set can't contain (1,2) and (1,1).There exists only a function within the specific interval. For instance, f(x) = x within -1 ≤ x ≤ 1 and x + 2 within 1 < x ≤ 3. If f(x) = x and x + 2 within -1 ≤ x ≤ 1, then this doesn't make an equation the function.

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      If an equation is a function, then:The set of coordinates doesn't consists of the same first member. For instance, the set can't contain (1,2) and (1,1).There exists only a function within the specific interval. For instance, f(x) = x within -1 ≤ x ≤ 1 and x + 2 within 1 < x ≤ 3. If f(x) = x and x + 2 within -1 ≤ x ≤ 1, then this doesn't make an equation the function.
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