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How do you determine which two numbers a square root is between? - Answers

You need to know (or be able to find) perfect squares. Suppose you want to find two numbers that the square root of 27 is between. You need to find a number, N, such that N2 < 27 but the square of the next number is bigger ie (N + 1)2 > 27 The nearest perfect squares, on either side of 27 are 25 and 36. That is, 25 < 27 < 36 Taking square roots, 5 < sqrt(27) < 6 However, it is also true that -6 < sqrt(27) < -5



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How do you determine which two numbers a square root is between? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_determine_which_two_numbers_a_square_root_is_between

You need to know (or be able to find) perfect squares. Suppose you want to find two numbers that the square root of 27 is between. You need to find a number, N, such that N2 < 27 but the square of the next number is bigger ie (N + 1)2 > 27 The nearest perfect squares, on either side of 27 are 25 and 36. That is, 25 < 27 < 36 Taking square roots, 5 < sqrt(27) < 6 However, it is also true that -6 < sqrt(27) < -5



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https://math.answers.com/math-and-arithmetic/How_do_you_determine_which_two_numbers_a_square_root_is_between

How do you determine which two numbers a square root is between? - Answers

You need to know (or be able to find) perfect squares. Suppose you want to find two numbers that the square root of 27 is between. You need to find a number, N, such that N2 < 27 but the square of the next number is bigger ie (N + 1)2 > 27 The nearest perfect squares, on either side of 27 are 25 and 36. That is, 25 < 27 < 36 Taking square roots, 5 < sqrt(27) < 6 However, it is also true that -6 < sqrt(27) < -5

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      You need to know (or be able to find) perfect squares. Suppose you want to find two numbers that the square root of 27 is between. You need to find a number, N, such that N2 < 27 but the square of the next number is bigger ie (N + 1)2 > 27 The nearest perfect squares, on either side of 27 are 25 and 36. That is, 25 < 27 < 36 Taking square roots, 5 < sqrt(27) < 6 However, it is also true that -6 < sqrt(27) < -5

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