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How do you divid 36 boy in 9 room a odd number? - Answers

To divide 36 boys into 9 rooms with an odd number of boys in each room, you can place 1 boy in one room and then distribute the remaining 35 boys among the other 8 rooms. This can be done by placing 5 boys in each of those 8 rooms, resulting in an odd count in one room and even counts in the others. However, it’s impossible to have all rooms contain an odd number of boys while maintaining the total of 36, since an odd count multiplied by an odd number of rooms results in an odd total. Thus, the task is not feasible under these conditions.



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How do you divid 36 boy in 9 room a odd number? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_divid_36_boy_in_9_room_a_odd_number

To divide 36 boys into 9 rooms with an odd number of boys in each room, you can place 1 boy in one room and then distribute the remaining 35 boys among the other 8 rooms. This can be done by placing 5 boys in each of those 8 rooms, resulting in an odd count in one room and even counts in the others. However, it’s impossible to have all rooms contain an odd number of boys while maintaining the total of 36, since an odd count multiplied by an odd number of rooms results in an odd total. Thus, the task is not feasible under these conditions.



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https://math.answers.com/math-and-arithmetic/How_do_you_divid_36_boy_in_9_room_a_odd_number

How do you divid 36 boy in 9 room a odd number? - Answers

To divide 36 boys into 9 rooms with an odd number of boys in each room, you can place 1 boy in one room and then distribute the remaining 35 boys among the other 8 rooms. This can be done by placing 5 boys in each of those 8 rooms, resulting in an odd count in one room and even counts in the others. However, it’s impossible to have all rooms contain an odd number of boys while maintaining the total of 36, since an odd count multiplied by an odd number of rooms results in an odd total. Thus, the task is not feasible under these conditions.

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      To divide 36 boys into 9 rooms with an odd number of boys in each room, you can place 1 boy in one room and then distribute the remaining 35 boys among the other 8 rooms. This can be done by placing 5 boys in each of those 8 rooms, resulting in an odd count in one room and even counts in the others. However, it’s impossible to have all rooms contain an odd number of boys while maintaining the total of 36, since an odd count multiplied by an odd number of rooms results in an odd total. Thus, the task is not feasible under these conditions.
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