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How do you divide numbers in standard form? - Answers

Suppose a = w*10x and b = y*10z are the two numbers is standard form. Then the mantissae, w and y, belong to the interval [1, 10), and x and z are integers.a/b = (w*10x)/(y*10z) = (w/y)*10x-zIf w≥y thenw/y lies in the interval [1, 10), and the above is the answer to the division.If w



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How do you divide numbers in standard form? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_divide_numbers_in_standard_form

Suppose a = w*10x and b = y*10z are the two numbers is standard form. Then the mantissae, w and y, belong to the interval [1, 10), and x and z are integers.a/b = (w*10x)/(y*10z) = (w/y)*10x-zIf w≥y thenw/y lies in the interval [1, 10), and the above is the answer to the division.If w



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https://math.answers.com/math-and-arithmetic/How_do_you_divide_numbers_in_standard_form

How do you divide numbers in standard form? - Answers

Suppose a = w*10x and b = y*10z are the two numbers is standard form. Then the mantissae, w and y, belong to the interval [1, 10), and x and z are integers.a/b = (w*10x)/(y*10z) = (w/y)*10x-zIf w≥y thenw/y lies in the interval [1, 10), and the above is the answer to the division.If w

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      Suppose a = w*10x and b = y*10z are the two numbers is standard form. Then the mantissae, w and y, belong to the interval [1, 10), and x and z are integers.a/b = (w*10x)/(y*10z) = (w/y)*10x-zIf w≥y thenw/y lies in the interval [1, 10), and the above is the answer to the division.If w

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