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How do you do 6(5-2x) -4(3x 1)? - Answers

This is done by using a method called the distributive property. This is actually quite simple if we had x(y+z) we would distribute that xx, and get xy+xz. This is what we will use to solve this problem.If we take 6(5-2x) -4(3x+1) I have made the + sign bold, assuming that this is the symbol there.So next we'd use the distributive property and get 30-12x-12x-4.Now we would combine like terms, and get 26-24x.



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How do you do 6(5-2x) -4(3x 1)? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_do_6(5-2x)_-4(3x_1)

This is done by using a method called the distributive property. This is actually quite simple if we had x(y+z) we would distribute that xx, and get xy+xz. This is what we will use to solve this problem.If we take 6(5-2x) -4(3x+1) I have made the + sign bold, assuming that this is the symbol there.So next we'd use the distributive property and get 30-12x-12x-4.Now we would combine like terms, and get 26-24x.



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https://math.answers.com/math-and-arithmetic/How_do_you_do_6(5-2x)_-4(3x_1)

How do you do 6(5-2x) -4(3x 1)? - Answers

This is done by using a method called the distributive property. This is actually quite simple if we had x(y+z) we would distribute that xx, and get xy+xz. This is what we will use to solve this problem.If we take 6(5-2x) -4(3x+1) I have made the + sign bold, assuming that this is the symbol there.So next we'd use the distributive property and get 30-12x-12x-4.Now we would combine like terms, and get 26-24x.

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      This is done by using a method called the distributive property. This is actually quite simple if we had x(y+z) we would distribute that xx, and get xy+xz. This is what we will use to solve this problem.If we take 6(5-2x) -4(3x+1) I have made the + sign bold, assuming that this is the symbol there.So next we'd use the distributive property and get 30-12x-12x-4.Now we would combine like terms, and get 26-24x.

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