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https://math.answers.com/math-and-arithmetic/How_do_you_factor_10x2_plus_27x_-_28

How do you factor 10x2 plus 27x - 28? - Answers

To factor: 10x2 + 27x - 28 Find two values that add up to 27, our middle coefficient, and which multiply to make -280, the product of the other two coefficients. In this case, those two values would be 35 and -8. Now break the middle term down with those two values, and factor: = 10x2 + 35x - 8x - 28 = 5x(2x + 7) - 4(2x + 7) = (5x - 4)(2x + 7)



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How do you factor 10x2 plus 27x - 28? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_factor_10x2_plus_27x_-_28

To factor: 10x2 + 27x - 28 Find two values that add up to 27, our middle coefficient, and which multiply to make -280, the product of the other two coefficients. In this case, those two values would be 35 and -8. Now break the middle term down with those two values, and factor: = 10x2 + 35x - 8x - 28 = 5x(2x + 7) - 4(2x + 7) = (5x - 4)(2x + 7)



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https://math.answers.com/math-and-arithmetic/How_do_you_factor_10x2_plus_27x_-_28

How do you factor 10x2 plus 27x - 28? - Answers

To factor: 10x2 + 27x - 28 Find two values that add up to 27, our middle coefficient, and which multiply to make -280, the product of the other two coefficients. In this case, those two values would be 35 and -8. Now break the middle term down with those two values, and factor: = 10x2 + 35x - 8x - 28 = 5x(2x + 7) - 4(2x + 7) = (5x - 4)(2x + 7)

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      To factor: 10x2 + 27x - 28 Find two values that add up to 27, our middle coefficient, and which multiply to make -280, the product of the other two coefficients. In this case, those two values would be 35 and -8. Now break the middle term down with those two values, and factor: = 10x2 + 35x - 8x - 28 = 5x(2x + 7) - 4(2x + 7) = (5x - 4)(2x + 7)

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