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How do you factor 20x2 plus 22x-12? - Answers

20x^2 + 22x - 12 Since '2' is a common factor Then 2(10x^2 + 11x -6) To factor the bracket bit , we write down all the factors of '10' & '6' Hence 10 ; 1,2,5,10, 6 ; 1,2,3,6. We then select a pair of numbers from each factors to multiply together and then add/subtract to reach '11'. They are ( 2,5) & ( 2,3) 3 x 5 = 15 & 2 x 2 = 4 15 - 4 = 11 So (2,3) & ( 2,5) are the selected factors. Open brakets. ( 5x 2)(2x 3) To select the signs, we note that '6' is a minus '-6' , so the signs are differen(+/-). We also note that 11x is positive (+) , so the larger multiple is the positive multip;le and the small is the negative. Hence (5x - 2)(2x + 3) Overall it is 2(5x - 2)(2x + 3)



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How do you factor 20x2 plus 22x-12? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_factor_20x2_plus_22x-12

20x^2 + 22x - 12 Since '2' is a common factor Then 2(10x^2 + 11x -6) To factor the bracket bit , we write down all the factors of '10' & '6' Hence 10 ; 1,2,5,10, 6 ; 1,2,3,6. We then select a pair of numbers from each factors to multiply together and then add/subtract to reach '11'. They are ( 2,5) & ( 2,3) 3 x 5 = 15 & 2 x 2 = 4 15 - 4 = 11 So (2,3) & ( 2,5) are the selected factors. Open brakets. ( 5x 2)(2x 3) To select the signs, we note that '6' is a minus '-6' , so the signs are differen(+/-). We also note that 11x is positive (+) , so the larger multiple is the positive multip;le and the small is the negative. Hence (5x - 2)(2x + 3) Overall it is 2(5x - 2)(2x + 3)



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https://math.answers.com/math-and-arithmetic/How_do_you_factor_20x2_plus_22x-12

How do you factor 20x2 plus 22x-12? - Answers

20x^2 + 22x - 12 Since '2' is a common factor Then 2(10x^2 + 11x -6) To factor the bracket bit , we write down all the factors of '10' & '6' Hence 10 ; 1,2,5,10, 6 ; 1,2,3,6. We then select a pair of numbers from each factors to multiply together and then add/subtract to reach '11'. They are ( 2,5) & ( 2,3) 3 x 5 = 15 & 2 x 2 = 4 15 - 4 = 11 So (2,3) & ( 2,5) are the selected factors. Open brakets. ( 5x 2)(2x 3) To select the signs, we note that '6' is a minus '-6' , so the signs are differen(+/-). We also note that 11x is positive (+) , so the larger multiple is the positive multip;le and the small is the negative. Hence (5x - 2)(2x + 3) Overall it is 2(5x - 2)(2x + 3)

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      20x^2 + 22x - 12 Since '2' is a common factor Then 2(10x^2 + 11x -6) To factor the bracket bit , we write down all the factors of '10' & '6' Hence 10 ; 1,2,5,10, 6 ; 1,2,3,6. We then select a pair of numbers from each factors to multiply together and then add/subtract to reach '11'. They are ( 2,5) & ( 2,3) 3 x 5 = 15 & 2 x 2 = 4 15 - 4 = 11 So (2,3) & ( 2,5) are the selected factors. Open brakets. ( 5x 2)(2x 3) To select the signs, we note that '6' is a minus '-6' , so the signs are differen(+/-). We also note that 11x is positive (+) , so the larger multiple is the positive multip;le and the small is the negative. Hence (5x - 2)(2x + 3) Overall it is 2(5x - 2)(2x + 3)

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