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How do you factor 2x squared minus13x plus 20 equals 0? - Answers

Usually the easiest way to solve this kind of problem is to find two numbers whose sum is equal to the coefficient of the middle term, and whose product is equal to the product of the coefficients of the first and last terms. So in this case, we would want a product of 40, and a sum of -13. The only numbers that meet that condition are -8 and -5, so we'll use those, breaking the middle term down into two separate terms: 2x2 - 13x + 20 = 0 ∴ 2x2 - 8x - 5x + 20 = 0 Now you can take a common factor out of both the first two terms and the last two terms, and group the like terms together, resulting in the answer you seek: ∴ 2x(x - 4) - 5(x - 4) = 0 ∴ (2x - 5)(x - 4) = 0 ∴ x ∈ {2.5, 4}



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How do you factor 2x squared minus13x plus 20 equals 0? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_factor_2x_squared_minus13x_plus_20_equals_0

Usually the easiest way to solve this kind of problem is to find two numbers whose sum is equal to the coefficient of the middle term, and whose product is equal to the product of the coefficients of the first and last terms. So in this case, we would want a product of 40, and a sum of -13. The only numbers that meet that condition are -8 and -5, so we'll use those, breaking the middle term down into two separate terms: 2x2 - 13x + 20 = 0 ∴ 2x2 - 8x - 5x + 20 = 0 Now you can take a common factor out of both the first two terms and the last two terms, and group the like terms together, resulting in the answer you seek: ∴ 2x(x - 4) - 5(x - 4) = 0 ∴ (2x - 5)(x - 4) = 0 ∴ x ∈ {2.5, 4}



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https://math.answers.com/math-and-arithmetic/How_do_you_factor_2x_squared_minus13x_plus_20_equals_0

How do you factor 2x squared minus13x plus 20 equals 0? - Answers

Usually the easiest way to solve this kind of problem is to find two numbers whose sum is equal to the coefficient of the middle term, and whose product is equal to the product of the coefficients of the first and last terms. So in this case, we would want a product of 40, and a sum of -13. The only numbers that meet that condition are -8 and -5, so we'll use those, breaking the middle term down into two separate terms: 2x2 - 13x + 20 = 0 ∴ 2x2 - 8x - 5x + 20 = 0 Now you can take a common factor out of both the first two terms and the last two terms, and group the like terms together, resulting in the answer you seek: ∴ 2x(x - 4) - 5(x - 4) = 0 ∴ (2x - 5)(x - 4) = 0 ∴ x ∈ {2.5, 4}

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      Usually the easiest way to solve this kind of problem is to find two numbers whose sum is equal to the coefficient of the middle term, and whose product is equal to the product of the coefficients of the first and last terms. So in this case, we would want a product of 40, and a sum of -13. The only numbers that meet that condition are -8 and -5, so we'll use those, breaking the middle term down into two separate terms: 2x2 - 13x + 20 = 0 ∴ 2x2 - 8x - 5x + 20 = 0 Now you can take a common factor out of both the first two terms and the last two terms, and group the like terms together, resulting in the answer you seek: ∴ 2x(x - 4) - 5(x - 4) = 0 ∴ (2x - 5)(x - 4) = 0 ∴ x ∈ {2.5, 4}
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