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How do you factor 9x2 plus 3x - 2? - Answers

You can do this by finding two numbers whose product is equal to the product of the coefficients on the first and last terms, and whose sum is equal to the coefficient of the middle term. So we want two numbers, call them A and B, that add to make 3 and multiply to make -2 * 9, or -18. Those numbers would be six and negative three. You can take those numbers and break the middle term down into two terms using them as their coefficients: 9x2 + 3x - 2 = 9x2 + 6x - 3x - 2 Now factor out like terms: = 3x(3x + 2) - 1(3x + 2) And group: = (3x - 1)(3x + 2)



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How do you factor 9x2 plus 3x - 2? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_factor_9x2_plus_3x_-_2

You can do this by finding two numbers whose product is equal to the product of the coefficients on the first and last terms, and whose sum is equal to the coefficient of the middle term. So we want two numbers, call them A and B, that add to make 3 and multiply to make -2 * 9, or -18. Those numbers would be six and negative three. You can take those numbers and break the middle term down into two terms using them as their coefficients: 9x2 + 3x - 2 = 9x2 + 6x - 3x - 2 Now factor out like terms: = 3x(3x + 2) - 1(3x + 2) And group: = (3x - 1)(3x + 2)



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https://math.answers.com/math-and-arithmetic/How_do_you_factor_9x2_plus_3x_-_2

How do you factor 9x2 plus 3x - 2? - Answers

You can do this by finding two numbers whose product is equal to the product of the coefficients on the first and last terms, and whose sum is equal to the coefficient of the middle term. So we want two numbers, call them A and B, that add to make 3 and multiply to make -2 * 9, or -18. Those numbers would be six and negative three. You can take those numbers and break the middle term down into two terms using them as their coefficients: 9x2 + 3x - 2 = 9x2 + 6x - 3x - 2 Now factor out like terms: = 3x(3x + 2) - 1(3x + 2) And group: = (3x - 1)(3x + 2)

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      You can do this by finding two numbers whose product is equal to the product of the coefficients on the first and last terms, and whose sum is equal to the coefficient of the middle term. So we want two numbers, call them A and B, that add to make 3 and multiply to make -2 * 9, or -18. Those numbers would be six and negative three. You can take those numbers and break the middle term down into two terms using them as their coefficients: 9x2 + 3x - 2 = 9x2 + 6x - 3x - 2 Now factor out like terms: = 3x(3x + 2) - 1(3x + 2) And group: = (3x - 1)(3x + 2)

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