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How do you factor a quadratic equation without a b value? - Answers

A quadratic, of the form ax2 + c can always be factorised as a(x2 + c/a). It can be factorised into real linear factors only if c is negative. So suppose c = -d where d is positive. Then ax2 - d = a(x2 - d/a) = a*[x - √(d/a)]*[x + √(d/a)] The linear factors are rational only if d/a is a rational square.



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How do you factor a quadratic equation without a b value? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_factor_a_quadratic_equation_without_a_b_value

A quadratic, of the form ax2 + c can always be factorised as a(x2 + c/a). It can be factorised into real linear factors only if c is negative. So suppose c = -d where d is positive. Then ax2 - d = a(x2 - d/a) = a*[x - √(d/a)]*[x + √(d/a)] The linear factors are rational only if d/a is a rational square.



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https://math.answers.com/math-and-arithmetic/How_do_you_factor_a_quadratic_equation_without_a_b_value

How do you factor a quadratic equation without a b value? - Answers

A quadratic, of the form ax2 + c can always be factorised as a(x2 + c/a). It can be factorised into real linear factors only if c is negative. So suppose c = -d where d is positive. Then ax2 - d = a(x2 - d/a) = a*[x - √(d/a)]*[x + √(d/a)] The linear factors are rational only if d/a is a rational square.

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      A quadratic, of the form ax2 + c can always be factorised as a(x2 + c/a). It can be factorised into real linear factors only if c is negative. So suppose c = -d where d is positive. Then ax2 - d = a(x2 - d/a) = a*[x - √(d/a)]*[x + √(d/a)] The linear factors are rational only if d/a is a rational square.

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