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How do you factor z squared plus 7z plus 6? - Answers

The procedure for factoring z2+7z+6 is as follows: First, we must look at the number in front of the first variable. In this case, it is a 1. Then we look at the last number in the expression, which is a 6 (the expression must be arranged in descending order by the exponents of the variables). Now, we multiply these two numbers together. 1 x 6 = 6 We need to factors of 6 that when added together equal 7. The factors of 6 are as follows 1 x 6 2 x 3 The first set of factors is the only set that adds up to equal 7. So now we break apart the middle term into 1 and 6, so that it looks like this: z2+z+6z+6 Now we group the expression like this (z2+z)+(6z+6) With the parenthesis like this, we can begin pulling out common factors, leaving the expression looking like this z(z+1)+6(z+1) Because the contents of the sets of parenthesis are the same, we can combine the z and the 6 to get the fully-factored expression (z+6)(z+1)



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How do you factor z squared plus 7z plus 6? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_factor_z_squared_plus_7z_plus_6

The procedure for factoring z2+7z+6 is as follows: First, we must look at the number in front of the first variable. In this case, it is a 1. Then we look at the last number in the expression, which is a 6 (the expression must be arranged in descending order by the exponents of the variables). Now, we multiply these two numbers together. 1 x 6 = 6 We need to factors of 6 that when added together equal 7. The factors of 6 are as follows 1 x 6 2 x 3 The first set of factors is the only set that adds up to equal 7. So now we break apart the middle term into 1 and 6, so that it looks like this: z2+z+6z+6 Now we group the expression like this (z2+z)+(6z+6) With the parenthesis like this, we can begin pulling out common factors, leaving the expression looking like this z(z+1)+6(z+1) Because the contents of the sets of parenthesis are the same, we can combine the z and the 6 to get the fully-factored expression (z+6)(z+1)



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https://math.answers.com/math-and-arithmetic/How_do_you_factor_z_squared_plus_7z_plus_6

How do you factor z squared plus 7z plus 6? - Answers

The procedure for factoring z2+7z+6 is as follows: First, we must look at the number in front of the first variable. In this case, it is a 1. Then we look at the last number in the expression, which is a 6 (the expression must be arranged in descending order by the exponents of the variables). Now, we multiply these two numbers together. 1 x 6 = 6 We need to factors of 6 that when added together equal 7. The factors of 6 are as follows 1 x 6 2 x 3 The first set of factors is the only set that adds up to equal 7. So now we break apart the middle term into 1 and 6, so that it looks like this: z2+z+6z+6 Now we group the expression like this (z2+z)+(6z+6) With the parenthesis like this, we can begin pulling out common factors, leaving the expression looking like this z(z+1)+6(z+1) Because the contents of the sets of parenthesis are the same, we can combine the z and the 6 to get the fully-factored expression (z+6)(z+1)

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      The procedure for factoring z2+7z+6 is as follows: First, we must look at the number in front of the first variable. In this case, it is a 1. Then we look at the last number in the expression, which is a 6 (the expression must be arranged in descending order by the exponents of the variables). Now, we multiply these two numbers together. 1 x 6 = 6 We need to factors of 6 that when added together equal 7. The factors of 6 are as follows 1 x 6 2 x 3 The first set of factors is the only set that adds up to equal 7. So now we break apart the middle term into 1 and 6, so that it looks like this: z2+z+6z+6 Now we group the expression like this (z2+z)+(6z+6) With the parenthesis like this, we can begin pulling out common factors, leaving the expression looking like this z(z+1)+6(z+1) Because the contents of the sets of parenthesis are the same, we can combine the z and the 6 to get the fully-factored expression (z+6)(z+1)
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