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How do you find all the factors of 54? - Answers

First, we notice it is even. Write 2 as a prime factor and divide it out.Now we have 27, which we notice is divisible by 3.We divide by 3 until we can't, and notice we do it three times and end up at 1.When we have 1, then we know all the prime factors.In this case, we have 54 = 2*3*3*3 = 2*33.= 21*33Notice the exponents are 1 and 3So we add one to these and multiply: 2*4 = 8.This means 54 has 8 factors, so we'll know if we miss any.To find the factors, just look for all the ways we can multiply with one 2 and three 3s.We have, 1, 2, 3, 6, 9, 18, 27, and 54.As there are eight, we know we didn't miss any.



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How do you find all the factors of 54? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_all_the_factors_of_54

First, we notice it is even. Write 2 as a prime factor and divide it out.Now we have 27, which we notice is divisible by 3.We divide by 3 until we can't, and notice we do it three times and end up at 1.When we have 1, then we know all the prime factors.In this case, we have 54 = 2*3*3*3 = 2*33.= 21*33Notice the exponents are 1 and 3So we add one to these and multiply: 2*4 = 8.This means 54 has 8 factors, so we'll know if we miss any.To find the factors, just look for all the ways we can multiply with one 2 and three 3s.We have, 1, 2, 3, 6, 9, 18, 27, and 54.As there are eight, we know we didn't miss any.



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https://math.answers.com/math-and-arithmetic/How_do_you_find_all_the_factors_of_54

How do you find all the factors of 54? - Answers

First, we notice it is even. Write 2 as a prime factor and divide it out.Now we have 27, which we notice is divisible by 3.We divide by 3 until we can't, and notice we do it three times and end up at 1.When we have 1, then we know all the prime factors.In this case, we have 54 = 2*3*3*3 = 2*33.= 21*33Notice the exponents are 1 and 3So we add one to these and multiply: 2*4 = 8.This means 54 has 8 factors, so we'll know if we miss any.To find the factors, just look for all the ways we can multiply with one 2 and three 3s.We have, 1, 2, 3, 6, 9, 18, 27, and 54.As there are eight, we know we didn't miss any.

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      First, we notice it is even. Write 2 as a prime factor and divide it out.Now we have 27, which we notice is divisible by 3.We divide by 3 until we can't, and notice we do it three times and end up at 1.When we have 1, then we know all the prime factors.In this case, we have 54 = 2*3*3*3 = 2*33.= 21*33Notice the exponents are 1 and 3So we add one to these and multiply: 2*4 = 8.This means 54 has 8 factors, so we'll know if we miss any.To find the factors, just look for all the ways we can multiply with one 2 and three 3s.We have, 1, 2, 3, 6, 9, 18, 27, and 54.As there are eight, we know we didn't miss any.

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