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How do you find final position in an velocity vs time graph? - Answers

I think you mean distance traveled. Every tiny period "dt" of time, the distance gone is the velocity at that time, times dt. Plot velocity against time. Each little slice of velocity times dt is a slice of the area. So the total distance is the total area under the graph from time t=0 to the finish, or to whatever time you want. This is the principle behind the Integral Calculus.



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How do you find final position in an velocity vs time graph? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_final_position_in_an_velocity_vs_time_graph

I think you mean distance traveled. Every tiny period "dt" of time, the distance gone is the velocity at that time, times dt. Plot velocity against time. Each little slice of velocity times dt is a slice of the area. So the total distance is the total area under the graph from time t=0 to the finish, or to whatever time you want. This is the principle behind the Integral Calculus.



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https://math.answers.com/math-and-arithmetic/How_do_you_find_final_position_in_an_velocity_vs_time_graph

How do you find final position in an velocity vs time graph? - Answers

I think you mean distance traveled. Every tiny period "dt" of time, the distance gone is the velocity at that time, times dt. Plot velocity against time. Each little slice of velocity times dt is a slice of the area. So the total distance is the total area under the graph from time t=0 to the finish, or to whatever time you want. This is the principle behind the Integral Calculus.

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      I think you mean distance traveled. Every tiny period "dt" of time, the distance gone is the velocity at that time, times dt. Plot velocity against time. Each little slice of velocity times dt is a slice of the area. So the total distance is the total area under the graph from time t=0 to the finish, or to whatever time you want. This is the principle behind the Integral Calculus.

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