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How do you find five consecutive numbers for 320? - Answers

To find five consecutive numbers that sum to 320, you can set up the equation where the middle number is ( x ). The five numbers would then be ( x - 2, x - 1, x, x + 1, x + 2 ). Their sum can be expressed as ( (x - 2) + (x - 1) + x + (x + 1) + (x + 2) = 5x ). Setting this equal to 320 gives ( 5x = 320 ), so ( x = 64 ). Therefore, the five consecutive numbers are 62, 63, 64, 65, and 66.



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How do you find five consecutive numbers for 320? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_five_consecutive_numbers_for_320

To find five consecutive numbers that sum to 320, you can set up the equation where the middle number is ( x ). The five numbers would then be ( x - 2, x - 1, x, x + 1, x + 2 ). Their sum can be expressed as ( (x - 2) + (x - 1) + x + (x + 1) + (x + 2) = 5x ). Setting this equal to 320 gives ( 5x = 320 ), so ( x = 64 ). Therefore, the five consecutive numbers are 62, 63, 64, 65, and 66.



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https://math.answers.com/math-and-arithmetic/How_do_you_find_five_consecutive_numbers_for_320

How do you find five consecutive numbers for 320? - Answers

To find five consecutive numbers that sum to 320, you can set up the equation where the middle number is ( x ). The five numbers would then be ( x - 2, x - 1, x, x + 1, x + 2 ). Their sum can be expressed as ( (x - 2) + (x - 1) + x + (x + 1) + (x + 2) = 5x ). Setting this equal to 320 gives ( 5x = 320 ), so ( x = 64 ). Therefore, the five consecutive numbers are 62, 63, 64, 65, and 66.

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      To find five consecutive numbers that sum to 320, you can set up the equation where the middle number is ( x ). The five numbers would then be ( x - 2, x - 1, x, x + 1, x + 2 ). Their sum can be expressed as ( (x - 2) + (x - 1) + x + (x + 1) + (x + 2) = 5x ). Setting this equal to 320 gives ( 5x = 320 ), so ( x = 64 ). Therefore, the five consecutive numbers are 62, 63, 64, 65, and 66.

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