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https://math.answers.com/math-and-arithmetic/How_do_you_find_intercept_and_slope

How do you find intercept and slope? - Answers

You mean y-intercept and gradient. For the y intercept you simply look at where the line crosses the y-axis- that's the the vertical one. If it crosses at (0,4) for example the y-intercept is 4 (if (0,6), it's 6 etc.) For the gradient you have to take two points on the line and do the following sum: change in y divided by change in x so if the first point is (3,3) and the second point is (4,8) then you do 8-5=change in y=3 4-3=change in x=1 and 3/1=3 so your gradient is 3. If you are looking for the equation of a straight line, you then fit it into y=mx+c where m is the gradient and c is the y-intercept. Hope that helps. =)



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How do you find intercept and slope? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_intercept_and_slope

You mean y-intercept and gradient. For the y intercept you simply look at where the line crosses the y-axis- that's the the vertical one. If it crosses at (0,4) for example the y-intercept is 4 (if (0,6), it's 6 etc.) For the gradient you have to take two points on the line and do the following sum: change in y divided by change in x so if the first point is (3,3) and the second point is (4,8) then you do 8-5=change in y=3 4-3=change in x=1 and 3/1=3 so your gradient is 3. If you are looking for the equation of a straight line, you then fit it into y=mx+c where m is the gradient and c is the y-intercept. Hope that helps. =)



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https://math.answers.com/math-and-arithmetic/How_do_you_find_intercept_and_slope

How do you find intercept and slope? - Answers

You mean y-intercept and gradient. For the y intercept you simply look at where the line crosses the y-axis- that's the the vertical one. If it crosses at (0,4) for example the y-intercept is 4 (if (0,6), it's 6 etc.) For the gradient you have to take two points on the line and do the following sum: change in y divided by change in x so if the first point is (3,3) and the second point is (4,8) then you do 8-5=change in y=3 4-3=change in x=1 and 3/1=3 so your gradient is 3. If you are looking for the equation of a straight line, you then fit it into y=mx+c where m is the gradient and c is the y-intercept. Hope that helps. =)

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      You mean y-intercept and gradient. For the y intercept you simply look at where the line crosses the y-axis- that's the the vertical one. If it crosses at (0,4) for example the y-intercept is 4 (if (0,6), it's 6 etc.) For the gradient you have to take two points on the line and do the following sum: change in y divided by change in x so if the first point is (3,3) and the second point is (4,8) then you do 8-5=change in y=3 4-3=change in x=1 and 3/1=3 so your gradient is 3. If you are looking for the equation of a straight line, you then fit it into y=mx+c where m is the gradient and c is the y-intercept. Hope that helps. =)

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