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How do you find mode if mean and median is given? - Answers

With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.



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How do you find mode if mean and median is given? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_mode_if_mean_and_median_is_given

With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.



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https://math.answers.com/math-and-arithmetic/How_do_you_find_mode_if_mean_and_median_is_given

How do you find mode if mean and median is given? - Answers

With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.

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      With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.
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