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How do you find the LCD when subtracting rational expressions? - Answers

Given two fractions, you find the Least Common Denominator by finding the Least Common Multiple of the two Denominators. Then for each fraction, the new numerator the product of the is old numerator, and whatever multiplier you use to get the new denominator. Example: 1/14 - 1/21: The LCM of 14 & 21 is 42, so for the first fraction: 3 x 14 = 42, so the new numerator is 3 x 1 = 3. For the 2nd fraction: 2 x 21 = 42, so the new numerator is 2 x 1 = 2. The new subtraction problem is: 3/42 - 2/42 = 1/42



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How do you find the LCD when subtracting rational expressions? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_the_LCD_when_subtracting_rational_expressions

Given two fractions, you find the Least Common Denominator by finding the Least Common Multiple of the two Denominators. Then for each fraction, the new numerator the product of the is old numerator, and whatever multiplier you use to get the new denominator. Example: 1/14 - 1/21: The LCM of 14 & 21 is 42, so for the first fraction: 3 x 14 = 42, so the new numerator is 3 x 1 = 3. For the 2nd fraction: 2 x 21 = 42, so the new numerator is 2 x 1 = 2. The new subtraction problem is: 3/42 - 2/42 = 1/42



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https://math.answers.com/math-and-arithmetic/How_do_you_find_the_LCD_when_subtracting_rational_expressions

How do you find the LCD when subtracting rational expressions? - Answers

Given two fractions, you find the Least Common Denominator by finding the Least Common Multiple of the two Denominators. Then for each fraction, the new numerator the product of the is old numerator, and whatever multiplier you use to get the new denominator. Example: 1/14 - 1/21: The LCM of 14 & 21 is 42, so for the first fraction: 3 x 14 = 42, so the new numerator is 3 x 1 = 3. For the 2nd fraction: 2 x 21 = 42, so the new numerator is 2 x 1 = 2. The new subtraction problem is: 3/42 - 2/42 = 1/42

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      Given two fractions, you find the Least Common Denominator by finding the Least Common Multiple of the two Denominators. Then for each fraction, the new numerator the product of the is old numerator, and whatever multiplier you use to get the new denominator. Example: 1/14 - 1/21: The LCM of 14 & 21 is 42, so for the first fraction: 3 x 14 = 42, so the new numerator is 3 x 1 = 3. For the 2nd fraction: 2 x 21 = 42, so the new numerator is 2 x 1 = 2. The new subtraction problem is: 3/42 - 2/42 = 1/42

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