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How do you find the percent ionic character? - Answers

Using the difference of ionic electronegativity expressed/designated as XA and XB. The formula is written as %IC={1-exp[(-0.25)(XA-XB)^2]}*100. the procedure is put in your electronegativities, (the order doesn't matter because we square the difference) and then square the difference. Then multiply that by -0.25 and put it on the exp, which you then subtract from one and times by 100. The exp is the way they write e^x for some reason. Example: %IC of TiO2 electronegativity: Ti=1.5 O=3.5 %IC={1-e^[(-0.25)(1.5-3.5)^2]}*100 1.5-3.5=-2 %IC={1-e^[(-0.25)(-2)^2]}*100 -2^2=4 %IC={1-e^[(-0.25)4]}*100 -0.25*4=-1 %IC={1-e^-1}*100 e^-1=0.367879441 %IC={1- 0.367879441 }*100 1- 0.367879441=0.632120559 %IC=0.632120559*100 0.632120559*100=63.2120559 Do your rounding, add a % sign and %IC of TiO2= 63%



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How do you find the percent ionic character? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_the_percent_ionic_character

Using the difference of ionic electronegativity expressed/designated as XA and XB. The formula is written as %IC={1-exp[(-0.25)(XA-XB)^2]}*100. the procedure is put in your electronegativities, (the order doesn't matter because we square the difference) and then square the difference. Then multiply that by -0.25 and put it on the exp, which you then subtract from one and times by 100. The exp is the way they write e^x for some reason. Example: %IC of TiO2 electronegativity: Ti=1.5 O=3.5 %IC={1-e^[(-0.25)(1.5-3.5)^2]}*100 1.5-3.5=-2 %IC={1-e^[(-0.25)(-2)^2]}*100 -2^2=4 %IC={1-e^[(-0.25)4]}*100 -0.25*4=-1 %IC={1-e^-1}*100 e^-1=0.367879441 %IC={1- 0.367879441 }*100 1- 0.367879441=0.632120559 %IC=0.632120559*100 0.632120559*100=63.2120559 Do your rounding, add a % sign and %IC of TiO2= 63%



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https://math.answers.com/math-and-arithmetic/How_do_you_find_the_percent_ionic_character

How do you find the percent ionic character? - Answers

Using the difference of ionic electronegativity expressed/designated as XA and XB. The formula is written as %IC={1-exp[(-0.25)(XA-XB)^2]}*100. the procedure is put in your electronegativities, (the order doesn't matter because we square the difference) and then square the difference. Then multiply that by -0.25 and put it on the exp, which you then subtract from one and times by 100. The exp is the way they write e^x for some reason. Example: %IC of TiO2 electronegativity: Ti=1.5 O=3.5 %IC={1-e^[(-0.25)(1.5-3.5)^2]}*100 1.5-3.5=-2 %IC={1-e^[(-0.25)(-2)^2]}*100 -2^2=4 %IC={1-e^[(-0.25)4]}*100 -0.25*4=-1 %IC={1-e^-1}*100 e^-1=0.367879441 %IC={1- 0.367879441 }*100 1- 0.367879441=0.632120559 %IC=0.632120559*100 0.632120559*100=63.2120559 Do your rounding, add a % sign and %IC of TiO2= 63%

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      Using the difference of ionic electronegativity expressed/designated as XA and XB. The formula is written as %IC={1-exp[(-0.25)(XA-XB)^2]}*100. the procedure is put in your electronegativities, (the order doesn't matter because we square the difference) and then square the difference. Then multiply that by -0.25 and put it on the exp, which you then subtract from one and times by 100. The exp is the way they write e^x for some reason. Example: %IC of TiO2 electronegativity: Ti=1.5 O=3.5 %IC={1-e^[(-0.25)(1.5-3.5)^2]}*100 1.5-3.5=-2 %IC={1-e^[(-0.25)(-2)^2]}*100 -2^2=4 %IC={1-e^[(-0.25)4]}*100 -0.25*4=-1 %IC={1-e^-1}*100 e^-1=0.367879441 %IC={1- 0.367879441 }*100 1- 0.367879441=0.632120559 %IC=0.632120559*100 0.632120559*100=63.2120559 Do your rounding, add a % sign and %IC of TiO2= 63%

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