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How do you find the variance of a set of numbers? - Answers

1. Find the arithmetic mean (average)2. Find the distance of each number from the mean (x-the mean=?)3. Square each number4. Add up all of the squares5. Divide the final sum by the original meanEX: Set: 1, 3, 4, 5, 71. 1 + 3 + 4 + 5 + 7 = 20 / 5 = 42. 1-4=-3 3-4=-1 4-4=0 5-4=17-4=33. 3*3=9 1*1=1 0*0=0 1*1=13*3=94. 9 + 1 + 0 + 1 + 9 = 205. 20 / 4 = 5



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How do you find the variance of a set of numbers? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_the_variance_of_a_set_of_numbers

1. Find the arithmetic mean (average)2. Find the distance of each number from the mean (x-the mean=?)3. Square each number4. Add up all of the squares5. Divide the final sum by the original meanEX: Set: 1, 3, 4, 5, 71. 1 + 3 + 4 + 5 + 7 = 20 / 5 = 42. 1-4=-3 3-4=-1 4-4=0 5-4=17-4=33. 3*3=9 1*1=1 0*0=0 1*1=13*3=94. 9 + 1 + 0 + 1 + 9 = 205. 20 / 4 = 5



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https://math.answers.com/math-and-arithmetic/How_do_you_find_the_variance_of_a_set_of_numbers

How do you find the variance of a set of numbers? - Answers

1. Find the arithmetic mean (average)2. Find the distance of each number from the mean (x-the mean=?)3. Square each number4. Add up all of the squares5. Divide the final sum by the original meanEX: Set: 1, 3, 4, 5, 71. 1 + 3 + 4 + 5 + 7 = 20 / 5 = 42. 1-4=-3 3-4=-1 4-4=0 5-4=17-4=33. 3*3=9 1*1=1 0*0=0 1*1=13*3=94. 9 + 1 + 0 + 1 + 9 = 205. 20 / 4 = 5

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      1. Find the arithmetic mean (average)2. Find the distance of each number from the mean (x-the mean=?)3. Square each number4. Add up all of the squares5. Divide the final sum by the original meanEX: Set: 1, 3, 4, 5, 71. 1 + 3 + 4 + 5 + 7 = 20 / 5 = 42. 1-4=-3 3-4=-1 4-4=0 5-4=17-4=33. 3*3=9 1*1=1 0*0=0 1*1=13*3=94. 9 + 1 + 0 + 1 + 9 = 205. 20 / 4 = 5

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