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How do you find the y coordinate vertex of a parabola? - Answers
Example: Vertical velocity component of a 100 m/s cannonball fired at 30 degrees from horizontal = sin 30 * 100 = 50 m/s Find the maximum height reached. Take acceleration due to gravity at 10 (m/s)/s so: u = 50 m/s v = 0 a = - 10 m/s/s (approx) s = ? Using: v2 = u2 + ( 2 * a * s ) so: s = ( v2 - u2 ) / ( 2 * a ) s = ( 0 - 2500 ) / ( 2 * -10 ) s = 125 metres
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How do you find the y coordinate vertex of a parabola? - Answers
Example: Vertical velocity component of a 100 m/s cannonball fired at 30 degrees from horizontal = sin 30 * 100 = 50 m/s Find the maximum height reached. Take acceleration due to gravity at 10 (m/s)/s so: u = 50 m/s v = 0 a = - 10 m/s/s (approx) s = ? Using: v2 = u2 + ( 2 * a * s ) so: s = ( v2 - u2 ) / ( 2 * a ) s = ( 0 - 2500 ) / ( 2 * -10 ) s = 125 metres
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How do you find the y coordinate vertex of a parabola? - Answers
Example: Vertical velocity component of a 100 m/s cannonball fired at 30 degrees from horizontal = sin 30 * 100 = 50 m/s Find the maximum height reached. Take acceleration due to gravity at 10 (m/s)/s so: u = 50 m/s v = 0 a = - 10 m/s/s (approx) s = ? Using: v2 = u2 + ( 2 * a * s ) so: s = ( v2 - u2 ) / ( 2 * a ) s = ( 0 - 2500 ) / ( 2 * -10 ) s = 125 metres
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