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How do you find vertical velocity and vertical distance? - Answers

The answer will depend on the conditions under which the body is moving and how sophisticated your calculations need to be. On (or near) the surface of the earth, if the body had velocity v0 ms-1 at time t0 seconds then in the simple model, its velocity at time t seconds will be v = v0 - 9.81*t ms-1 (approx). The vertical distance will be v0t - 9.81t2 metres. In a more sophisticated model you would include air resistance. Also if v0 is large, it is possible that the height attained is large enough to affect deceleration due to gravity.



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How do you find vertical velocity and vertical distance? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_vertical_velocity_and_vertical_distance

The answer will depend on the conditions under which the body is moving and how sophisticated your calculations need to be. On (or near) the surface of the earth, if the body had velocity v0 ms-1 at time t0 seconds then in the simple model, its velocity at time t seconds will be v = v0 - 9.81*t ms-1 (approx). The vertical distance will be v0t - 9.81t2 metres. In a more sophisticated model you would include air resistance. Also if v0 is large, it is possible that the height attained is large enough to affect deceleration due to gravity.



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https://math.answers.com/math-and-arithmetic/How_do_you_find_vertical_velocity_and_vertical_distance

How do you find vertical velocity and vertical distance? - Answers

The answer will depend on the conditions under which the body is moving and how sophisticated your calculations need to be. On (or near) the surface of the earth, if the body had velocity v0 ms-1 at time t0 seconds then in the simple model, its velocity at time t seconds will be v = v0 - 9.81*t ms-1 (approx). The vertical distance will be v0t - 9.81t2 metres. In a more sophisticated model you would include air resistance. Also if v0 is large, it is possible that the height attained is large enough to affect deceleration due to gravity.

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      The answer will depend on the conditions under which the body is moving and how sophisticated your calculations need to be. On (or near) the surface of the earth, if the body had velocity v0 ms-1 at time t0 seconds then in the simple model, its velocity at time t seconds will be v = v0 - 9.81*t ms-1 (approx). The vertical distance will be v0t - 9.81t2 metres. In a more sophisticated model you would include air resistance. Also if v0 is large, it is possible that the height attained is large enough to affect deceleration due to gravity.

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