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How do you get 33 using 1234 once? - Answers

To get 33 using the digits 1, 2, 3, and 4 exactly once, you can perform the following calculation: ( 4 \times (3 + 2) + 1 ). This simplifies to ( 4 \times 5 + 1 = 20 + 1 = 21 ), which is incorrect. However, if you take a different approach, you can also express it as ( 12 + 34 - 13 = 33 ).



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How do you get 33 using 1234 once? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_get_33_using_1234_once

To get 33 using the digits 1, 2, 3, and 4 exactly once, you can perform the following calculation: ( 4 \times (3 + 2) + 1 ). This simplifies to ( 4 \times 5 + 1 = 20 + 1 = 21 ), which is incorrect. However, if you take a different approach, you can also express it as ( 12 + 34 - 13 = 33 ).



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https://math.answers.com/math-and-arithmetic/How_do_you_get_33_using_1234_once

How do you get 33 using 1234 once? - Answers

To get 33 using the digits 1, 2, 3, and 4 exactly once, you can perform the following calculation: ( 4 \times (3 + 2) + 1 ). This simplifies to ( 4 \times 5 + 1 = 20 + 1 = 21 ), which is incorrect. However, if you take a different approach, you can also express it as ( 12 + 34 - 13 = 33 ).

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      To get 33 using the digits 1, 2, 3, and 4 exactly once, you can perform the following calculation: ( 4 \times (3 + 2) + 1 ). This simplifies to ( 4 \times 5 + 1 = 20 + 1 = 21 ), which is incorrect. However, if you take a different approach, you can also express it as ( 12 + 34 - 13 = 33 ).

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