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How do you graph 3x minus 4y plus 4 equals 0? - Answers
Get some graph paper. Draw some axis (x and y) Solve your equation over and over for each value of x. 3x-4y+4=0 3x+4=4y (3/4) x = y So for: x=1 , y=0.75 x=2 , y=1.5 x=3, y=2.25 x=4, y=3 Now, slightly easier since we actually know from the form of the equation that it's a straight line y=mx+c being the straight line equation. c is where the line hits the y axis (in this case at 0) and m is the "gradient of the line" we actually only need to solve it twice and draw a straight line through the points. I'd suggest x=0 and x=4 as they are nice easy points.
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How do you graph 3x minus 4y plus 4 equals 0? - Answers
Get some graph paper. Draw some axis (x and y) Solve your equation over and over for each value of x. 3x-4y+4=0 3x+4=4y (3/4) x = y So for: x=1 , y=0.75 x=2 , y=1.5 x=3, y=2.25 x=4, y=3 Now, slightly easier since we actually know from the form of the equation that it's a straight line y=mx+c being the straight line equation. c is where the line hits the y axis (in this case at 0) and m is the "gradient of the line" we actually only need to solve it twice and draw a straight line through the points. I'd suggest x=0 and x=4 as they are nice easy points.
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How do you graph 3x minus 4y plus 4 equals 0? - Answers
Get some graph paper. Draw some axis (x and y) Solve your equation over and over for each value of x. 3x-4y+4=0 3x+4=4y (3/4) x = y So for: x=1 , y=0.75 x=2 , y=1.5 x=3, y=2.25 x=4, y=3 Now, slightly easier since we actually know from the form of the equation that it's a straight line y=mx+c being the straight line equation. c is where the line hits the y axis (in this case at 0) and m is the "gradient of the line" we actually only need to solve it twice and draw a straight line through the points. I'd suggest x=0 and x=4 as they are nice easy points.
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