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How do you graph 4x-5y-25? - Answers

To graph the equation (4x - 5y - 25 = 0), first, rearrange it into slope-intercept form (y = mx + b). Start by isolating (y): (5y = 4x - 25) and then (y = \frac{4}{5}x - 5). This shows the slope is (\frac{4}{5}) and the y-intercept is (-5). Plot the y-intercept at (0, -5), then use the slope to find another point by going up 4 units and right 5 units from the y-intercept. Finally, draw a straight line through these points.



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How do you graph 4x-5y-25? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_graph_4x-5y-25

To graph the equation (4x - 5y - 25 = 0), first, rearrange it into slope-intercept form (y = mx + b). Start by isolating (y): (5y = 4x - 25) and then (y = \frac{4}{5}x - 5). This shows the slope is (\frac{4}{5}) and the y-intercept is (-5). Plot the y-intercept at (0, -5), then use the slope to find another point by going up 4 units and right 5 units from the y-intercept. Finally, draw a straight line through these points.



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https://math.answers.com/math-and-arithmetic/How_do_you_graph_4x-5y-25

How do you graph 4x-5y-25? - Answers

To graph the equation (4x - 5y - 25 = 0), first, rearrange it into slope-intercept form (y = mx + b). Start by isolating (y): (5y = 4x - 25) and then (y = \frac{4}{5}x - 5). This shows the slope is (\frac{4}{5}) and the y-intercept is (-5). Plot the y-intercept at (0, -5), then use the slope to find another point by going up 4 units and right 5 units from the y-intercept. Finally, draw a straight line through these points.

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      To graph the equation (4x - 5y - 25 = 0), first, rearrange it into slope-intercept form (y = mx + b). Start by isolating (y): (5y = 4x - 25) and then (y = \frac{4}{5}x - 5). This shows the slope is (\frac{4}{5}) and the y-intercept is (-5). Plot the y-intercept at (0, -5), then use the slope to find another point by going up 4 units and right 5 units from the y-intercept. Finally, draw a straight line through these points.

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