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How do you graph y- 7x equals 49? - Answers
y - 7x = 49 can be put into slope-intercept form by adding 7x to both sides. This gives you y = 7x + 49. This means that the slope of the line is 7, and the y-intercept is 49. So, plot the point (0,49). After that, for every time x increases by 1, y increases by 7. So, plot the point (1,56). Draw a straight line between (0,49) and (1,56) and draw arrow heads on both ends of the line to indicate that it continues infinitely.
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How do you graph y- 7x equals 49? - Answers
y - 7x = 49 can be put into slope-intercept form by adding 7x to both sides. This gives you y = 7x + 49. This means that the slope of the line is 7, and the y-intercept is 49. So, plot the point (0,49). After that, for every time x increases by 1, y increases by 7. So, plot the point (1,56). Draw a straight line between (0,49) and (1,56) and draw arrow heads on both ends of the line to indicate that it continues infinitely.
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How do you graph y- 7x equals 49? - Answers
y - 7x = 49 can be put into slope-intercept form by adding 7x to both sides. This gives you y = 7x + 49. This means that the slope of the line is 7, and the y-intercept is 49. So, plot the point (0,49). After that, for every time x increases by 1, y increases by 7. So, plot the point (1,56). Draw a straight line between (0,49) and (1,56) and draw arrow heads on both ends of the line to indicate that it continues infinitely.
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- og:descriptiony - 7x = 49 can be put into slope-intercept form by adding 7x to both sides. This gives you y = 7x + 49. This means that the slope of the line is 7, and the y-intercept is 49. So, plot the point (0,49). After that, for every time x increases by 1, y increases by 7. So, plot the point (1,56). Draw a straight line between (0,49) and (1,56) and draw arrow heads on both ends of the line to indicate that it continues infinitely.
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