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How do you make a graph from an equation? - Answers

finding the equation of a line of (-1,2) and (1,2): formula: y=mx+b m = slope b = y intercept first find m: m=(y2-y1)/(x2-x1) so, m=(2-2)/ (1- -1) m=0 since you now know m you can plug that in to the formula: y=0x+b to get b: plug in the coordinates (either (-1,2) or (1,2)), it comes out the same (-1,2). y=mx+b or 2=0 × -1+b, ==>solving for b: b=2-(0)(-1). b=2 (1,2). y=mx+b or 2=0 × 1+b, ==>solving for b: b=2-(0)(1). b=2 you now know that m=0 and b=2, now plug that back in the equation to get: y=mx+b y=0x+2 y+2 It's confusing, but it works!



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How do you make a graph from an equation? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_make_a_graph_from_an_equation

finding the equation of a line of (-1,2) and (1,2): formula: y=mx+b m = slope b = y intercept first find m: m=(y2-y1)/(x2-x1) so, m=(2-2)/ (1- -1) m=0 since you now know m you can plug that in to the formula: y=0x+b to get b: plug in the coordinates (either (-1,2) or (1,2)), it comes out the same (-1,2). y=mx+b or 2=0 × -1+b, ==>solving for b: b=2-(0)(-1). b=2 (1,2). y=mx+b or 2=0 × 1+b, ==>solving for b: b=2-(0)(1). b=2 you now know that m=0 and b=2, now plug that back in the equation to get: y=mx+b y=0x+2 y+2 It's confusing, but it works!



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https://math.answers.com/math-and-arithmetic/How_do_you_make_a_graph_from_an_equation

How do you make a graph from an equation? - Answers

finding the equation of a line of (-1,2) and (1,2): formula: y=mx+b m = slope b = y intercept first find m: m=(y2-y1)/(x2-x1) so, m=(2-2)/ (1- -1) m=0 since you now know m you can plug that in to the formula: y=0x+b to get b: plug in the coordinates (either (-1,2) or (1,2)), it comes out the same (-1,2). y=mx+b or 2=0 × -1+b, ==>solving for b: b=2-(0)(-1). b=2 (1,2). y=mx+b or 2=0 × 1+b, ==>solving for b: b=2-(0)(1). b=2 you now know that m=0 and b=2, now plug that back in the equation to get: y=mx+b y=0x+2 y+2 It's confusing, but it works!

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      finding the equation of a line of (-1,2) and (1,2): formula: y=mx+b m = slope b = y intercept first find m: m=(y2-y1)/(x2-x1) so, m=(2-2)/ (1- -1) m=0 since you now know m you can plug that in to the formula: y=0x+b to get b: plug in the coordinates (either (-1,2) or (1,2)), it comes out the same (-1,2). y=mx+b or 2=0 × -1+b, ==>solving for b: b=2-(0)(-1). b=2 (1,2). y=mx+b or 2=0 × 1+b, ==>solving for b: b=2-(0)(1). b=2 you now know that m=0 and b=2, now plug that back in the equation to get: y=mx+b y=0x+2 y+2 It's confusing, but it works!

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