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https://math.answers.com/math-and-arithmetic/How_do_you_reduce_improper_fraction_to_its_lowest_terms

How do you reduce improper fraction to its lowest terms? - Answers

First you gotta see the denominator, like if it was 17/3, you would see how many times "3 goes into 17", as a simple way to put it, without actually going over it. Then since it goes into 17 5 times(3*5=15), so you are left with the remainder, which is 2. Then simply you put that over the divsor, so the end result would be 5 2/3.



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How do you reduce improper fraction to its lowest terms? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_reduce_improper_fraction_to_its_lowest_terms

First you gotta see the denominator, like if it was 17/3, you would see how many times "3 goes into 17", as a simple way to put it, without actually going over it. Then since it goes into 17 5 times(3*5=15), so you are left with the remainder, which is 2. Then simply you put that over the divsor, so the end result would be 5 2/3.



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https://math.answers.com/math-and-arithmetic/How_do_you_reduce_improper_fraction_to_its_lowest_terms

How do you reduce improper fraction to its lowest terms? - Answers

First you gotta see the denominator, like if it was 17/3, you would see how many times "3 goes into 17", as a simple way to put it, without actually going over it. Then since it goes into 17 5 times(3*5=15), so you are left with the remainder, which is 2. Then simply you put that over the divsor, so the end result would be 5 2/3.

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      First you gotta see the denominator, like if it was 17/3, you would see how many times "3 goes into 17", as a simple way to put it, without actually going over it. Then since it goes into 17 5 times(3*5=15), so you are left with the remainder, which is 2. Then simply you put that over the divsor, so the end result would be 5 2/3.

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