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How do you show that sinx divided by tanx equals cosx? - Answers

Let: o = opposite h = hypotenuse a = adjacent sin = o/h; tan = o/a Therefore, sin/tan = (o/h)/(o/a) = (o/h)*(a/o) = a/h = cos

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How do you show that sinx divided by tanx equals cosx? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_show_that_sinx_divided_by_tanx_equals_cosx

Let: o = opposite h = hypotenuse a = adjacent sin = o/h; tan = o/a Therefore, sin/tan = (o/h)/(o/a) = (o/h)*(a/o) = a/h = cos

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https://math.answers.com/math-and-arithmetic/How_do_you_show_that_sinx_divided_by_tanx_equals_cosx

How do you show that sinx divided by tanx equals cosx? - Answers

Let: o = opposite h = hypotenuse a = adjacent sin = o/h; tan = o/a Therefore, sin/tan = (o/h)/(o/a) = (o/h)*(a/o) = a/h = cos

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  Let: o = opposite h = hypotenuse a = adjacent sin = o/h; tan = o/a Therefore, sin/tan = (o/h)/(o/a) = (o/h)*(a/o) = a/h = cos
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