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How do you solve 20x2 plus 27x plus 9 equals 0? - Answers
20x^2 + 27x + 9 = 0 20x^2 + 15x +12x + 9 = 0 5x(4x + 3) + 3(4x + 3) = 0 (5x + 3)(4x + 3) = 0 So either (5x + 3) = 0 which yields x = -3/5 or (4x + 3) = 0 which yields x = -3/4
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How do you solve 20x2 plus 27x plus 9 equals 0? - Answers
https://math.answers.com/math-and-arithmetic/How_do_you_solve_20x2_plus_27x_plus_9_equals_0
20x^2 + 27x + 9 = 0 20x^2 + 15x +12x + 9 = 0 5x(4x + 3) + 3(4x + 3) = 0 (5x + 3)(4x + 3) = 0 So either (5x + 3) = 0 which yields x = -3/5 or (4x + 3) = 0 which yields x = -3/4
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How do you solve 20x2 plus 27x plus 9 equals 0? - Answers
20x^2 + 27x + 9 = 0 20x^2 + 15x +12x + 9 = 0 5x(4x + 3) + 3(4x + 3) = 0 (5x + 3)(4x + 3) = 0 So either (5x + 3) = 0 which yields x = -3/5 or (4x + 3) = 0 which yields x = -3/4
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- og:description20x^2 + 27x + 9 = 0 20x^2 + 15x +12x + 9 = 0 5x(4x + 3) + 3(4x + 3) = 0 (5x + 3)(4x + 3) = 0 So either (5x + 3) = 0 which yields x = -3/5 or (4x + 3) = 0 which yields x = -3/4
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