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How do you solve 2x-1 times 3x plus 5 equals 5? - Answers

(2x-1)*(3x+5)=5Use foil's method. First Outside Inside Last for multiplyingthe equation turns out to this(2x*3x)+(2x*5)+-(1*3x)+-(1*6)=5Solve within the parentheses.6x2+ 10x+-3x+-6=5Continue to solve6x2+7x+-6=5You need to make =5 to =06x2+7x+-6+-5=5-56x2+7x+-11=0quadratic formula is x=[-b +- {b^2*(-4ac)^2}]/2athere are two equations to solve. the number and the opposite of a number



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How do you solve 2x-1 times 3x plus 5 equals 5? - Answers

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(2x-1)*(3x+5)=5Use foil's method. First Outside Inside Last for multiplyingthe equation turns out to this(2x*3x)+(2x*5)+-(1*3x)+-(1*6)=5Solve within the parentheses.6x2+ 10x+-3x+-6=5Continue to solve6x2+7x+-6=5You need to make =5 to =06x2+7x+-6+-5=5-56x2+7x+-11=0quadratic formula is x=[-b +- {b^2*(-4ac)^2}]/2athere are two equations to solve. the number and the opposite of a number



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How do you solve 2x-1 times 3x plus 5 equals 5? - Answers

(2x-1)*(3x+5)=5Use foil's method. First Outside Inside Last for multiplyingthe equation turns out to this(2x*3x)+(2x*5)+-(1*3x)+-(1*6)=5Solve within the parentheses.6x2+ 10x+-3x+-6=5Continue to solve6x2+7x+-6=5You need to make =5 to =06x2+7x+-6+-5=5-56x2+7x+-11=0quadratic formula is x=[-b +- {b^2*(-4ac)^2}]/2athere are two equations to solve. the number and the opposite of a number

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      (2x-1)*(3x+5)=5Use foil's method. First Outside Inside Last for multiplyingthe equation turns out to this(2x*3x)+(2x*5)+-(1*3x)+-(1*6)=5Solve within the parentheses.6x2+ 10x+-3x+-6=5Continue to solve6x2+7x+-6=5You need to make =5 to =06x2+7x+-6+-5=5-56x2+7x+-11=0quadratic formula is x=[-b +- {b^2*(-4ac)^2}]/2athere are two equations to solve. the number and the opposite of a number

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