math.answers.com/math-and-arithmetic/How_do_you_solve_4X_squared_plus_8X_minus_20_equals_0

Preview meta tags from the math.answers.com website.

Linked Hostnames

8

Thumbnail

Search Engine Appearance

Google

https://math.answers.com/math-and-arithmetic/How_do_you_solve_4X_squared_plus_8X_minus_20_equals_0

How do you solve 4X squared plus 8X minus 20 equals 0? - Answers

-- Although not required, you can make it slightly easier on yourselfif you first divide each side of the equation by 4.-- Either way, you're left with a quadratic equation that isn't easilyfactorable by inspection, so you're forced to use the quadratic formulawhich you learned and then forgot.-- The quadratic formula says that when you have the quadratic equation[ Ax2 + Bx + C = 0 ],which is exactly what you have, the two solutions arex = 1/2A [ -B + sqrt(B2-4AC) ]andx = 1/2A [ -B - sqrt(B2-4AC) ].This is the perfect time to use the quadratic formula,and that's exactly how you solve your equation.



Bing

How do you solve 4X squared plus 8X minus 20 equals 0? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_4X_squared_plus_8X_minus_20_equals_0

-- Although not required, you can make it slightly easier on yourselfif you first divide each side of the equation by 4.-- Either way, you're left with a quadratic equation that isn't easilyfactorable by inspection, so you're forced to use the quadratic formulawhich you learned and then forgot.-- The quadratic formula says that when you have the quadratic equation[ Ax2 + Bx + C = 0 ],which is exactly what you have, the two solutions arex = 1/2A [ -B + sqrt(B2-4AC) ]andx = 1/2A [ -B - sqrt(B2-4AC) ].This is the perfect time to use the quadratic formula,and that's exactly how you solve your equation.



DuckDuckGo

https://math.answers.com/math-and-arithmetic/How_do_you_solve_4X_squared_plus_8X_minus_20_equals_0

How do you solve 4X squared plus 8X minus 20 equals 0? - Answers

-- Although not required, you can make it slightly easier on yourselfif you first divide each side of the equation by 4.-- Either way, you're left with a quadratic equation that isn't easilyfactorable by inspection, so you're forced to use the quadratic formulawhich you learned and then forgot.-- The quadratic formula says that when you have the quadratic equation[ Ax2 + Bx + C = 0 ],which is exactly what you have, the two solutions arex = 1/2A [ -B + sqrt(B2-4AC) ]andx = 1/2A [ -B - sqrt(B2-4AC) ].This is the perfect time to use the quadratic formula,and that's exactly how you solve your equation.

  • General Meta Tags

    22
    • title
      How do you solve 4X squared plus 8X minus 20 equals 0? - Answers
    • charset
      utf-8
    • Content-Type
      text/html; charset=utf-8
    • viewport
      minimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
    • X-UA-Compatible
      IE=edge,chrome=1

  • Open Graph Meta Tags

    7
    • og:image
      https://st.answers.com/html_test_assets/Answers_Blue.jpeg
    • og:image:width
      900
    • og:image:height
      900
    • og:site_name
      Answers
    • og:description
      -- Although not required, you can make it slightly easier on yourselfif you first divide each side of the equation by 4.-- Either way, you're left with a quadratic equation that isn't easilyfactorable by inspection, so you're forced to use the quadratic formulawhich you learned and then forgot.-- The quadratic formula says that when you have the quadratic equation[ Ax2 + Bx + C = 0 ],which is exactly what you have, the two solutions arex = 1/2A [ -B + sqrt(B2-4AC) ]andx = 1/2A [ -B - sqrt(B2-4AC) ].This is the perfect time to use the quadratic formula,and that's exactly how you solve your equation.

  • Twitter Meta Tags

    1
    • twitter:card
      summary_large_image

  • Link Tags

    16
    • alternate
      https://www.answers.com/feed.rss
    • apple-touch-icon
      /icons/180x180.png
    • canonical
      https://math.answers.com/math-and-arithmetic/How_do_you_solve_4X_squared_plus_8X_minus_20_equals_0
    • icon
      /favicon.svg
    • icon
      /icons/16x16.png

Links

60