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How do you solve sin2x plus sinX equals 0? - Answers

Sin(2x) + Sin(x) = 0 2Sin(x)Cos(x) + Sin(x) = 0 Factor 'Sin*(x)' Sin(x) (2Cos(x) + 1 = 0 Hence Sin(x) = 0 x = 0 , 180(pi) , 360(2pi) et.seq., & 2Cos(x) = -1 Cos(x) = -1/2 = -0.5 x = 120, 150, 480, et.seq.,



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How do you solve sin2x plus sinX equals 0? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_sin2x_plus_sinX_equals_0

Sin(2x) + Sin(x) = 0 2Sin(x)Cos(x) + Sin(x) = 0 Factor 'Sin*(x)' Sin(x) (2Cos(x) + 1 = 0 Hence Sin(x) = 0 x = 0 , 180(pi) , 360(2pi) et.seq., & 2Cos(x) = -1 Cos(x) = -1/2 = -0.5 x = 120, 150, 480, et.seq.,



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https://math.answers.com/math-and-arithmetic/How_do_you_solve_sin2x_plus_sinX_equals_0

How do you solve sin2x plus sinX equals 0? - Answers

Sin(2x) + Sin(x) = 0 2Sin(x)Cos(x) + Sin(x) = 0 Factor 'Sin*(x)' Sin(x) (2Cos(x) + 1 = 0 Hence Sin(x) = 0 x = 0 , 180(pi) , 360(2pi) et.seq., & 2Cos(x) = -1 Cos(x) = -1/2 = -0.5 x = 120, 150, 480, et.seq.,

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      Sin(2x) + Sin(x) = 0 2Sin(x)Cos(x) + Sin(x) = 0 Factor 'Sin*(x)' Sin(x) (2Cos(x) + 1 = 0 Hence Sin(x) = 0 x = 0 , 180(pi) , 360(2pi) et.seq., & 2Cos(x) = -1 Cos(x) = -1/2 = -0.5 x = 120, 150, 480, et.seq.,

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